All categories

3 years ago

Isabella went to the salon and was charged $72.60 for a cut and color. She added 20% to the cost as a

Mathematics

1 answer:

Tanya [424]3 years ago

3 0

A. assuming the sales tax is already added to the 72.60 all you have to do is add 20%

You might be interested in

(-6)(2)+(-8/4)<br>What is the Value of this Expression

Sedbober [7]

Answer:

i dont know im sorry but i will still try

5 0

3 years ago

Need help w/ #2.<br> I forgot how to do this.

vagabundo [1.1K]

The equation for a graph is y=mx+b, with m being the slope

In the given equation, -0.25 is the slope of the given line
This can also be written as - $\frac{1}{4}$

To find a perpendicular graph, you find the reciprocal of the slope
To do this, you switch the numerator and the denominator

Your final answer will be:
- $\frac{4}{1}$ which simplifies to -4

4 0

3 years ago

What is the slope of the line that passes through 4,-2 and -8,6

maria [59]

Answer:

Slope is -2/3

Step-by-step explanation:

5 0

3 years ago

Use the discriminant to describe the roots of each equation. Then select the best description. x^2 + 9x + 14 = 0

NISA [10]

given a quadratic equation in standard form

ax² + bx + c = 0

Then we can describe the nature of the roots using the discriminant

Δ = b² - 4ac

• if b² - 4ac > 0, then 2 real, distinct and irrational roots

• if b² - 4ac > 0 and a perfect square, then real and rational roots

• if b² - 4ac = 0, then real and equal roots

• if b² - 4ac < 0, then roots are not real

for x² + 9x + 14 = 0

with a = 1, b= 9 and c = 14, then

b² - 4ac = 9² - (4 × 1 × 14 ) = 81 - 56 = 25

Since b² - 4ac > 0 and a perfect square, then roots are real and rational

7 0

3 years ago

Match each function with its correct description. <br> HELP, picture attached.

Svetradugi [14.3K]

Answer:

1. (x+6)(2x - 3)(x - 1)²

2.(x-2)²(-2x - 1)²(-x + 1)

3. (-x + 1)³(x + 2)²(x - 3)

4. (-2x + 1)²(x - 3)²(x + 1)

Step-by-step explanation:

1. Degree 4, leading coefficient positive

(x+6)(2x - 3)(x - 1)²

That's the only equation with a degree of 4 (meaning x^4).

If you square the last parenthesis, you'll get an x^2, multiplied by the 2nd parenthesis you'll get an x^3 and multiply with the first parenthesis you'll get an x^4.

2. Degree is 5, leading coefficient is negative

(x-2)²(-2x - 1)²(-x + 1)

If you do the square of each of the first two parenthesis, you'll get something like (x²...)(4x²...)(-x + 1)

Multiply the first two parenthesis, to get (4x^4....)(-x + 1)

So, at the end you'll get -4x^5....

3. Degree 6, leading coefficient negative

(-x + 1)³(x + 2)²(x - 3)

That's the only equation of degree 6 given... so the choice is easy. Let's verify it's degree 6 and with negative leading coefficient.

Cube the first term and square the second one, you'll get something like...

(-x³...)(x²....)(x - 3)

If you combine all that you'll get something like -x^6....

4. Degree is 5, leading coefficient is positive

(-2x + 1)²(x - 3)²(x + 1)

If you do the square of each of the first two parenthesis, you'll get something like (4x²...)(x²...)(x + 1)

Multiply the first two parenthesis, to get (4x^4....)(x + 1)

So, at the end you'll get 4x^5....

3 0

3 years ago