Answer: Chemical Change
Explanation:
because it probably doesnt change the physical anatomy of the object only the atoms/ molecule relations
Answer:
physical properties:
It is a colorless, odorless and tasteless gas.
It readily dissolves in cold water.
It is highly reactive and form oxides with almost all elements except noble gases.
Liquid oxygen is strongly paramagnetic.
Chemical properties:
Oxygen is a highly reactive nonmetallic element; it is a strong oxidizing agent with high electronegativity and forms O 2 at Standard Temperature and Pressure (STP).
and i dont have any more for chemical, doggo sorry. :(
The balanced equation for the reaction between KOH and HF is
KOH + HF ---> KF + H₂O
stoichiometry of KOH to HF is 1:1
the number of HF moles reacted - 0.20 mol/L x 0.1000 L = 0.020 mol
the number of KOH moles reacted - 0.10 mol/L x 0.2000 L = 0.020 mol
KOH is a strong base and HF is a strong acid therefore they completely ionise into their corresponding ions
KOH --> K⁺ + OH⁻
HF ---> H⁺ + F⁻
number of H⁺ moles reacted = number of OH⁻ moles reacted
solution is completely neutralised no excess hydroxide or hydrogen ions
therefore when solution is neutral , pH = 7
pH of solution = 7
Answer:
peux tu me donner plus de précisions stp concernant le détail de calcul que tu souhaite avoir ?
Explanation:
The molecular formula of organic solvent is <em>C6H12</em>
<h2>calculation</h2><h3>find the empirical formula first as in step 1 and 2</h3>
Step 1: f<em>ind the moles of C and H</em>
- moles = % composition/molar mass
- from periodic table molar mass of C= 12 g/mol while that of H= 1 g/mol
- moles is C is therefore = 85.6/12= 7. 13 moles
- moles of H= 14.4/1 - 14.4 moles
Step 2: <em>calculate the mole fraction by dividing each mole by smallest number of mole(7.13)</em>
H= 14.4/7.13 =2
the empirical formula is therefore = CH2
<h2>Then calculate the molecular formula from empirical formula</h2>
step 3: divide the grams molar mass by empirical formula mass
empirical formula mass = 12+(1 x2) = 14 g/mol
= 84.2/ 14 = 6
step 4: multiply each of the subscript within the empirical formula with the value gotten in step 3
- that is [CH2]6 = C6H12 therefore the molecular formula = <u>C6H12</u>
