Answer:
![F= 17,075\ N](https://tex.z-dn.net/?f=F%3D%2017%2C075%5C%20N)
Explanation:
When the car is under an accelerating force and hits a tree, the instant force received by the tree is the same force that is accelerating the car.
The accelerating force can be calculated using Newton's second law:
![F=m\cdot a](https://tex.z-dn.net/?f=F%3Dm%5Ccdot%20a)
Where m is the mass of the car and a is the acceleration.
![F=3,415\ kg\cdot 5\ m/s^2](https://tex.z-dn.net/?f=F%3D3%2C415%5C%20kg%5Ccdot%205%5C%20m%2Fs%5E2)
![\boxed{F= 17,075\ N}](https://tex.z-dn.net/?f=%5Cboxed%7BF%3D%2017%2C075%5C%20N%7D)
Answer:
Technician A says that this is the normal operation of the ETC self -test is the correct answer.
Explanation:
An engine control unit (ECU), also widely referred to as an engine control module (ECM), is a type of electronic control device that controls an internal combustion engine with a series of actuators to ensure maximum engine performance.
It achieves so by reading values from a multitude of sensors within the engine bay, translating data using multidimensional feedback maps (the so-called lookup tables) and modifying the actuators.
Mechanically fixed and dynamically regulated by mechanical and pneumatic means, air-fuel combination, ignition time, and idle speed were before ECUs.
As soon as the system gets battery voltage, after ignition is turned, the efi computer makes a self-test of all the actuators and sensors, included the ETC.
I think your question should be:
An industrial laser is used to burn a hole through a piece of metal. The average intensity of the light is
![S = 1.23*10^9 W/m^2](https://tex.z-dn.net/?f=%20S%20%3D%201.23%2A10%5E9%20W%2Fm%5E2%20)
What is the rms value of (a) the electric field and
(b) the magnetic field in the electromagnetic wave emitted by the laser
Answer:
a) ![6.81*10^5 N/c](https://tex.z-dn.net/?f=%206.81%2A10%5E5%20N%2Fc%20)
b) ![2.27*10^3 T](https://tex.z-dn.net/?f=%202.27%2A10%5E3%20T%20)
Explanation:
To find the RMS value of the electric field, let's use the formula:
![E_r_m_s = sqrt*(S / CE_o)](https://tex.z-dn.net/?f=%20E_r_m_s%20%3D%20sqrt%2A%28S%20%2F%20CE_o%29)
Where
;
;
![S = 1.23*10^9 W/m^2](https://tex.z-dn.net/?f=%20%20S%20%3D%201.23%2A10%5E9%20W%2Fm%5E2%20)
Therefore
![E_r_m_s = sqrt*{(1.239*10^9W/m^2) / [(3.00*10^8m/s)*(8.85*10^-^1^2C^2/N.m^2)]}](https://tex.z-dn.net/?f=%20E_r_m_s%20%3D%20sqrt%2A%7B%281.239%2A10%5E9W%2Fm%5E2%29%20%2F%20%5B%283.00%2A10%5E8m%2Fs%29%2A%288.85%2A10%5E-%5E1%5E2C%5E2%2FN.m%5E2%29%5D%7D%20)
![E_r_m_s= 6.81 *10^5N/c](https://tex.z-dn.net/?f=%20E_r_m_s%3D%206.81%20%2A10%5E5N%2Fc%20)
b) to find the magnetic field in the electromagnetic wave emitted by the laser we use:
;
;
![B_r_m_s = 2.27*10^3 T](https://tex.z-dn.net/?f=%20B_r_m_s%20%3D%202.27%2A10%5E3%20T%20)
Answer:
I believe the correct answer is B..<u>" 1 "</u>
Explanation:
hope it helps! ;)