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pantera1 [17]
3 years ago
9

A land breeze forms when:

Physics
1 answer:
victus00 [196]3 years ago
7 0

Explanation:

Its D. The warm air from the land moves towards the water

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For questions 1 - 4 complete the representations for the four patterns below. Provide the mathematical
larisa [96]

Answer:

Explanation:

1

2

3

6 0
3 years ago
2. What is the water pressure at a depth of 24 m in a lake? [Density of water, p = 1 000 kg m- and gravitational acceleration, g
Andrei [34K]

Answer:

Pressure = ρgh

pressure (p) is measured in pascals (Pa)

density (ρ) is measured in kilograms per metre cubed (kg/m3)

The fore of gravitational field strength (g) is measured in N/kg or m/s 2

height of column (h) is measured in metres (m)

Answer = 235,200 Pa

Explanation:

Pressure = ρgh

Pressure = 1,000 x 9.8 x 24

Pressure = 235,200 Pa

4 0
2 years ago
Select the correct answer<br>What is the importance of writing a draft?​
givi [52]

Answer:to revise or edit

anything that can be made in the non draft one

Explanation:

4 0
3 years ago
A satellite at a particular point along an elliptical orbit has a gravitational potential energy of 5100 MJ with respect to Eart
serious [3.7K]

To solve this problem we will apply the theorem given in the conservation of energy, by which we have that it is conserved and that in terms of potential and kinetic energy, in their initial moment they must be equal to the final potential and kinetic energy. This is,

E_{initial} = E_{final}

PE_{initial}+KE_{initial} = PE_{final}+KE_{final}

Replacing the 5100MJ for satellite as initial potential energy, 4200MJ for initial kinetic energy and 5700MJ for final potential energy we have that

KE_{final} = (PE_{initial}+KE_{initial} )-PE_{final}

KE_{final} = (5100+4200)-5700

KE_{final} = 3600MJ

Therefore the final kinetic energy is 3600MJ

5 0
3 years ago
Un hamster esta sentado sobre un tocadisco cuya rapidez angular es constante si el hamster se mueve a un punto localizado al dob
kotegsom [21]

Answer:

b) se duplica

Explanation:

The disk is moving with constant angular velocity, let's call it \omega.

The linear velocity of a point on the disk is given by

v=\omega r

where r is the distance of the point from the axis of rotation.

In this problem, the object is moved at a distance twice as far as the initial point, so

r' = 2r

Therefore, the new linear velocity is

v'=\omega r' = \omega (2r) = 2 \omega r = 2 v

So, the velocity has doubled, and the correct answer is

b) se duplica

8 0
3 years ago
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