The spider will cross the driveway <u>25.71 in seconds</u>.
Why?
It's a conversion problem, so, in order to solve it, we need to convert the units of the given information.
Let's convert the given speed (in cm/s) to m/s.
We know that:
So, converting we have:
Then, calculating the time, we have:
We have that the spider will cross the driveway in 25.71 seconds.
Have a nice day!
Answer:
The maximum permissible propagation delay per flip flop stage is<u> 100 </u>n sec
Explanation:
1024 ripple counter has 10 J-K flip flops(210 = 1024).
So the total delay will be 10×x where x is the delay of each J-K flip flops.
The period of the clock pulse is 1× 10⁻⁶ s.
Now
10x <= 10⁻⁶ s
x <= 100 ns
x= 100 ns for prpoer operation.
pulse train with a frequency of 1 MHz is counted using a modulo-1024 ripple-counter built with J-K flip flops. For proper operation of the counter, the maximum permissible propagation delay per flip flop stage is <u>100 </u>n sec.
Answer:
Explanation:
Given that,
Mass per unit length is
μ = 4.87g/cm
μ=4.87g/cm × 1kg/1000g × 100cm/m
μ = 0.487kg/m
Tension
τ = 16.7N
Amplitude
A = 0.101mm
Frequency
f = 71 Hz
The wave is traveling in the negative direction
Given the wave form
y(x,t) = ym• Sin(kx + ωt)
A. Find ym?
ym is the amplitude of the waveform and it is given as
ym = A = 0.101mm
ym = 0.101mm
B. Find k?
k is the wavenumber and it can be determined using
k = 2π / λ
Then, we need to calculate the wavelength λ using
V = fλ
Then, λ = V/f
We have the frequency but we don't have the velocity, then we need to calculate the velocity using
v = √(τ/μ)
v = √(16.7/0.487)
v = 34.29
v = 5.86 m/s
Then, we can know the wavelength
λ = V/f = 5.86 / 71
λ = 0.0825 m
So, we can know the wavenumber
k = 2π/λ
k = 2π / 0.0825
k = 76.18 rad/m
C. Find ω?
This is the angular frequency and it can be determined using
ω = 2πf
ω = 2π × 71
ω = +446.11 rad/s
D. The angular frequency is positive (+) because the direction of propagation of wave is in the negative direction of x
Answer:
0.75 A
Explanation:
An electric current is a flow of charged particles.
A current is defined through its intensity, which is given by:
where
I is the current intensity
q is the charge passing through a given point in the circuit
t is the time it takes for the charge q to pass that point in the circuit
In this problem, we have:
q = 45 C is the charge passing through the point in the circuit
is the time elapsed
Therefore, the current intensity is:
Answer:
500 kg
Explanation:
using the formula Potential energy (p.e)=mgh where g= acceleration due to gravity whose value is 9.8
so,pe =mgh
622300=m*9.8*127
m=500kg
