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julia-pushkina [17]
3 years ago
7

*SCIENCE*

Chemistry
2 answers:
grigory [225]3 years ago
6 0
The gravitational pull between the gas and dust matter leads to the formation of new galaxies
GalinKa [24]3 years ago
3 0

Answer:

The gravitational pull between the gas and dust matter leads to the formation of new galaxies

Explanation:

My teacher went over the answers and said that one was correct.

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1) Calculate the molar mass of Tryptophan.
mestny [16]

Answer:

204.23 g/mol

Explanation:

6 0
3 years ago
Qofudowqfowefjwobfwofbwfofnroenennefeoiqefopne FREEE PONITTSS
Thepotemich [5.8K]
Hey lol
explanation:)))
5 0
3 years ago
Read 2 more answers
An evacuated 276 mL glass bulb weighs 129.6375 g. Filled with an unknown gas, the bulb weighs 130.0318 g. Calculate the gas dens
baherus [9]

Answer:

density=1.43 g/L

Explanation:

Since the density formula is density = mass / volume, we need to find out the mass of the gas and the volume is that of the container.

The mass of the gas is  130.0318 g-129.6375 g=0.3943 g

The gas volume is  276mL*(1L/1000mL) 0.276 L

density = mass / volume=0.3943g/0.276L

density =1.43g/L

5 0
3 years ago
Consider the following chemical reaction:
jolli1 [7]

From the calculation, the moles of water produced is 18 moles of water.

<h3>What is a decomposition reaction?</h3>

A decomposition reaction is one in which a substance is split up into smaller parts.

We have the reaction; 2 Cr(OH)3(aq) ------------> Cr2O3(s) + 3H2O(l)

From this reaction;

2 moles of  Cr(OH)3 produced 3 moles of water

12 moles of  Cr(OH)3 will produce;

12 moles  *  3 moles / 2moles

= 18 moles of water

Hence, 12 moles of chromium (III) hydroxide produces 18 moles of water.

Learn more about decomposition reaction:brainly.com/question/8009068?

#SPJ1

4 0
1 year ago
The acid-dissociation constant for benzoic acid (C6H5COOH) is 6.3×10−5. Calculate the equilibrium concentration of H3O+ in the s
raketka [301]

Answer : The equilibrium concentration of H_3O^+ in the solution is, 2.1\times 10^{-3}M

Explanation :

The dissociation of acid reaction is:

                       C_6H_5COOH+H_2O\rightarrow H_3O^++C_6H_5COO^-

Initial conc.        c                                 0                0

At eqm.             c-x                                 x                x

Given:

c = 7.0\times 10^{-2}M

K_a=6.3\times 10^{-5}

The expression of dissociation constant of acid is:

K_a=\frac{[H_3O^+][C_6H_5COO^-]}{[C_6H_5COOH]}

K_a=\frac{(x)\times (x)}{(c-x)}

Now put all the given values in this expression, we get:

6.3\times 10^{-5}=\frac{(x)\times (x)}{[(7.0\times 10^{-2})-x]}

x=2.1\times 10^{-3}M

Thus, the equilibrium concentration of H_3O^+ in the solution is, 2.1\times 10^{-3}M

4 0
3 years ago
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