Applying 1st law of thermodynamics:
Q = Delta U + WB
WB is the workdone by the system
<span>WB = 346 J </span>
As,
<span>Delta U = ( m ) ( CV ) ( T2 - T1 ) </span>
<span>CV = ( Delta U ) / ( m ) ( T2 - T1 )
</span>Putting the values in equation:
<span>CV = ( 8485 J ) / ( 80.0 g ) ( 225 C - 25 C ) </span>
<span>CV = 0.5303 J / g - C degree </span>
Now putting in original equation:
<span>Q = Delta U + WB </span>
<span>Q = ( 8485 ) + ( 346 ) = 8831 J
8831J is the specific heat of the gas</span>
Answer:
0.316 moles are produced.
Explanation:
We state the redox reaction:
4HNO₃ + Cu → Cu(NO₃)₂ + 2NO₂ + 2H₂O
We need to determine the limting reactant:
0.1 L . 14 M = 1.4 moles
10 g . 1mol/ 63.54g =0.158 mol
Cu is the limiting reactant. Let's see
4 moles of acid need 1 mol of Cu to react
1.4 moles of acid may react to (4 . 1) / 1.4 = 0.35 moles
We do not have enough Cu.
1 mol of Cu can produce 1 mol of NO₂
Then 0.158 moles will produce, 0.316 moles. (double of moles)
If we see stoichiometry, ratio is 1:2
The atomic radius of main group elements generally increases down a group because as there are more electrons they are farther away from the nucleus and the electrons closer to the nucleus shield the outer electrons from the protons for attraction.
