Answer:
Aquatic ecosystem has two components -
- Biotic components
2.Abiotic components
temperature and amount of sunlight are the part of abiotic component .
while living things like sponges and planktons are the biotic components of ecosystem.
Explanation:
aquatic components are of two types-
freshwater ecosystem( lakes and ponds, river and streams)
marine ecosystem(ocean ecosysyem, estuaries)
planktons-
planktons are found in limnetic zone, availability of sunlight is much here. planktons are zooplanktons and phytoplanktons are very important link in aquatic ecosystem.
sponges
In marine water, the <em>benthic zone</em> is the area below the<em> pelagic zone.</em> Here temperature decreased because of less light perception. This zone is very nutrient rich so organisms which are present here are- bacteria, fungi, sea anemone, sponges and some fishes.
Answer: Molarity is defined as moles of solute per liter of solution. So, find the moles of solute and divide by the liters of solution.
molar mass AlCl3 = 133g/mole
moles AlCl3 = 127 g x 1 mole/133 g = 0.955 moles
liters of solution = 400 ml x 1 liter/1000 ml = 0.400 liters
Molarity = 0.955 moles/0.400 liters = 2.39 M
Explain: I looked it up on wyzant.com
Answer:
To find the average atomic mass, you take a certain number of atoms, find the total mass of each isotope, and then divide the total mass of all the atoms by the total number of atoms. Assume that you have, say, 10 000 atoms of carbon
Explanation:
Answer: The correct answer is -297 kJ.
Explanation:
To solve this problem, we want to modify each of the equations given to get the equation at the bottom of the photo. To do this, we realize that we need SO2 on the right side of the equation (as a product). This lets us know that we must reverse the first equation. This gives us:
2SO3 —> O2 + 2SO2 (196 kJ)
Remember that we take the opposite of the enthalpy change (reverse the sign) when we reverse the equation.
Now, both equations have double the coefficients that we would like (for example, there is 2S in the second equation when we need only S). This means we should multiply each equation (and their enthalpy changes) by 1/2. This gives us:
SO3 —>1/2O2 + SO2 (98 kJ)
S + 3/2O2 —> SO3 (-395 kJ)
Now, we add the two equations together. Notice that the SO3 in the reactants in the first equation and the SO3 in the products of the second equation cancel. Also note that O2 is present on both sides of the equation, so we must subtract 3/2 - 1/2, giving us a net 1O2 on the left side of the equation.
S + O2 —> SO2
Now, we must add the enthalpies together to get our final answer.
-395 kJ + 98 kJ = -297 kJ
Hope this helps!
