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DIA [1.3K]
3 years ago
8

Here’s the answers I wasn’t asking a question hehe!Subtract the mass of the filter paper (0.27g) from the mass of the paper and

copper (0.98 g). Record the difference in the data table as the amount of copper.
You already converted mass to moles for the reactants. Now convert mass to moles for the product, copper


all for edge

ANSWERS!!!

Chemistry
1 answer:
GarryVolchara [31]3 years ago
4 0
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A)  Iris

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The Iris controls the diameter of the opening in your eye, thus also controlling the amount of light let inside. It's also reponsible for the colour of you eye.

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How many moles are in 4.6 x 10^19 atoms? <br><br> *#27 is the question
velikii [3]
There are 0.000076 moles in 4.6 x 10^19 atoms.
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3 years ago
Write the molecular formula for a compound with the possible elements C, H, N and O that exhibits a molecular ion at M
liberstina [14]

Answer:

= \mathbf{C_3H_6O}

Explanation:

From the given information, since the molecular mass of the ion M+ is not given;

Let's assume M+ = 58.0423

So, by applying the 13th rule;

we will need to divide the mass by 13, after dividing it;

The quotient n = no. of carbon; &

The addition of the quotient (n) with the remainder r =  no. of hydrogen.

So;

\dfrac{58}{13}= 4 \ remainder \ 6

So;

C_nH_{n+r} = C_4H_{4+6}

= C_4H_{10}

From the given information; we have oxygen present, so since the mass of oxygen = 16, we put oxygen in the molecular formula by removing CH_4. Also, since the mass is an even number then Nitrogen is 0.

So, we have:

= \mathbf{C_3H_6O}

6 0
2 years ago
Which subatomic particle will be attracted by a positively charged object?
anyanavicka [17]

Protons are Positively charged

Electrons are Negatively charged

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Hope this Helps!!!

4 0
3 years ago
Be sure to answer all parts. Consider the formation of ammonia in two experiments. (a) To a 1.00−L container at 727°C, 1.30 mol
Sonbull [250]

<u>Answer:</u> The value of K_c for 2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g) reaction is 5.13\times 10^2

<u>Explanation:</u>

We are given:

Initial moles of nitrogen gas = 1.30 moles

Initial moles of hydrogen gas = 1.65 moles

Equilibrium moles of ammonia = 0.100 moles

Volume of the container = 1.00 L

For the given chemical equation:

                N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)

<u>Initial:</u>            1.30       1.65

<u>At eqllm:</u>       1.30-x    1.65-3x             2x

Evaluating the value of 'x'

\Rightarrow 2x=0.100\\\\\Rightarrow x=0.050mol

The expression of K_c for above equation follows:

K_c=\frac{[NH_3]^2}{[N_2]\times [H_2]^3}

Equilibrium moles of nitrogen gas = (1.30-x)=(1.30-0.05)=1.25mol

Equilibrium moles of hydrogen gas = (1.65-x)=(1.65-0.05)=1.60mol

Putting values in above expression, we get:

K_c=\frac{(0.100)^2}{1.25\times (1.60)^3}\\\\K_c=1.95\times 10^{-3}

Calculating the K_c' for the given chemical equation:

2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g)

K_c'=\frac{1}{K_c}\\\\K_c'=\frac{1}{1.95\times 10^{-3}}=5.13\times 10^2

Hence, the value of K_c for 2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g) reaction is 5.13\times 10^2

8 0
3 years ago
Read 2 more answers
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