A minor league baseball 112 games in a session. If the team won 16 more than 3 times as many games as they lost, how many wins a
nd losses do they have
1 answer:
Answer:
- Won = 88 games
- Lost = 24 games
Step-by-step explanation:
The number of games for the session is 112 so all the wins and losses should add up to 112.
Assume that the number of times they lost is x. The number of times they won would then be: 16 + 3x
Total expression is therefore:
16 + 3x + x = 112
16 + 4x = 112
4x = 112 - 16
x = 96/4
x = 24
They lost 24 games. Number of games won is:
= 112 - 24
= 88 games
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