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Bad White [126]
3 years ago
13

Please I really need help

Chemistry
1 answer:
ella [17]3 years ago
3 0
The picture won’t load try messaging me !!
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Arrange the following units in decreasing order: nm,km,pm,Dm,mm,m,cm,hm,gm
goblinko [34]

The units are nm (nano-meter), km (kilo-meter), pm (pico-meter), dm (decimeter), mm (millimeter), m (meter), cm (centimeter), hm (hectometer) and gm (gigameter). Now we can express each of these units in terms of m.

1 nm = 10^{-9}m, 1 Km = 10^{3}m 1 pm = 10^{-12}m, 1 dm = 0.1 m, 1 mm = 0.001 m, 1 cm = 0.01 m, 1 hm = 100 m, 1 gm = 10^{9} m. Thus the decreasing unit will be

gm>km>hm>m>dm>cm>mm>nm>pm      

3 0
3 years ago
How many grams are in 0.02 moles of beryllium iodide, Bel2?
Flura [38]
This set up of a conversion table should show you that if you multiply the grams of BeI2 times .02 moles, it equals <span>5.256 g (your answer) </span>

8 0
3 years ago
Hello people ~
vodomira [7]

Answer:

Cutting the supply of oxygen

Explanation:

We know that a thing need three things to burn

  1. Oxygen
  2. Heat
  3. flammable object .

Co_2 stops oxygen supply so fire gets extinguished

5 0
3 years ago
How many grams of KCl (s) has been produced from the thermal decomposition of KClO3 (s) that produced 50.0 mL of O2 (g) at 25 de
geniusboy [140]

Answer:

The mass is m_{KCl} =  0.102 \ g

Explanation:

From the question we are told that

   The volume of oxygen produced is  V_o = 50mL  = 50 *10^{-3} L

    The temperature is T = 25 ^oC = 25* 273 = 298 K

     The pressure is  P = 1.0\  atm

From the ideal gas law we have that

      PV =  nRT

Where R is the gas constant  with the value

         R =  0.08206 \ atm \cdot L /mol K

  n is the number of moles making it the subject of the formula

          n = \frac{PV}{RT}

Substituting values

          n = \frac{1 * (50 *10^{-3}) }{0.08206 * 298}

          n =  2.045 *10^{-3} \  mol

From the chemical equation

      one mole of  KClO_3 produces one mole of  kCl and   \frac{3}{2} of oxygen

       x mole of  KClO_3 produces x mole of  kCl and   2.045 *10^{-3} \  mol of oxygen

So    x = \frac{2.045 *10^{-3}}{\frac{3}{2} }

      x =  \frac{2}{3} * 2.045 *10^{-3}

      x =  1.363 *10^{-3} \ mol

Now the molar mass of  KCl is a constant with a value

           M_{KCl} = 74.55  g/mol

Now the mass of KCl is mathematically evaluated as

          m_{KCl} = x * M_{KCl}

Substituting values

          m_{KCl} = 1.363 *10^{-3} * 74.55

         m_{KCl} =  0.102 \ g

6 0
3 years ago
What is the rate of change in velocity
luda_lava [24]
The rate of change in velocity<span> is called acceleration.</span>
3 0
4 years ago
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