Ask question

Ask question

All categories

4 years ago

8

5. Base your answer to the following question on the

2 answers:

KatRina [158]4 years ago

7 0

The answer is B) is the correct answer

elixir [45]4 years ago

4 0

Answer:

B) 2Crº + 6e- --> 2Cr3+

Explanation:

The process of oxidation is where electrons are lost. Thus, out of the 2 ions that change charge(Cr and Cu), we must choose the one where the oxidation number increases(which means electrons are lost). Cr goes from an oxidation number of 0 to an oxidation number of 3+, while Cu goes from an oxidation number of 2+ to 0. Thus, we are looking at the half reaction for Cr. Half reactions never have subtracting electrons, so the answer must be B. I am assuming that last plus should be a -->

You might be interested in

How often does the tip of and hour hand on a clock have the same velocity?

motikmotik

Answer:

Estoy triste, tuve que regalar a mi perro

8 0

3 years ago

Which reaction has a positive δs°? question 6 options:

Nastasia [14]

B. Because there are 3 molecules in right and 2 molecules in the left, so entropy rises.

3 0

3 years ago

Which of the following equations does not demonstrate the law of conservation of mass

tia_tia [17]

The answer is c :) i hope its the right answer

8 0

3 years ago

Read 2 more answers

I really need help ! This is science

lina2011 [118]

Answer:

7. genetics because hereditary is not the study of hereditary.

8. is hereditary because it is the study of how things pass on to next generation what is inherited.

7 0

3 years ago

Read 2 more answers

The NaCl crystal structure consists of alternating Na⁺ and Cl⁻ ions lying next to each other in three dimensions. If the Na⁺ rad

Yuliya22 [10]

Answer : The radii of the two ions Cl⁻ ion and Na⁺ ion is, 181 and 102 pm respectively.

Explanation :

As we are given that the Na⁺ radius is 56.4% of the Cl⁻ radius.

Let us assume that the radius of Cl⁻ be, (x) pm

So, the radius of Na⁺ = $x\times \frac{56.4}{100}=(0.564x)pm$

In the crystal structure of NaCl, 2 Cl⁻ ions present at the corner and 1 Na⁺ ion present at the edge of lattice.

Thus, the edge length is equal to the sum of 2 radius of Cl⁻ ion and 2 radius of Na⁺ ion.

Given:

Distance between Na⁺ nuclei = 566 pm

Thus, the relation will be:

$2\times \text{Radius of }Cl^-+2\times \text{Radius of }Na^+=\text{Distance between }Na^+\text{ nuclei}$

$2\times x+2\times 0.564x=566$

$2x+1.128x=566$

$3.128x=566$

$x=180.9\approx 181pm$

The radius of Cl⁻ ion = (x) pm = 181 pm

The radius of Na⁺ ion = (0.564x) pm = (0.564 × 181) pm =102.084 pm ≈ 102 pm

Thus, the radii of the two ions Cl⁻ ion and Na⁺ ion is, 181 and 102 pm respectively.

4 0

3 years ago