All categories

3 years ago

An increases in the pressure on a gas, increases the speed at which particles of

Chemistry

1 answer:

spayn [35]3 years ago

6 0

Answer:true

Explanation:

You might be interested in

Which are examples of dynamic equilibrium

sweet-ann [11.9K]

Answer:Dynamic Equilibrium Examples. Any reaction will be in dynamic equilibrium if it's reversible and the rates of the forward and reverse reactions are equal. For example, say that you prepare a solution that is saturated with an aqueous solution of NaCl.

Explanation:

8 0

2 years ago

Read 2 more answers

El sol es la estrella más grande

Misha Larkins [42]

Answer:

Schb

Explanation:

5 0

3 years ago

A gaseous system undergoes a change in temperature and volume. What is the entropy change for a particle in this system if the f

deff fn [24]

Explanation:

Entropy means the amount of randomness present within the molecules of the body of a substance.

Relation between entropy and microstate is as follows.

S = $K_{b} \times ln \Omega$

where, S = entropy

$K_{b}$ = Boltzmann constant

$\Omega$ = number of microstates

This equation only holds good when the system is neither losing or gaining energy. And, in the given situation we assume that the system is neither gaining or losing energy.

Also, let us assume that $\Omega$ = 1, and $\Omega'$ = 0.833

Therefore, change in entropy will be calculated as follows.

$\Delta S = K_{b} \times ln \Omega' - K_{b} \times ln \Omega$

= $1.38 \times 10^{-23} \times ln(0.833) - 1.38 \times 10^{-23} \times \times ln(1)$

= $1.38 \times 10^{-23} \times (-0.182)$

= $-0.251 \times 10^{-23}$

or, = $-2.51 \times 10^{-24}$

Thus, we can conclude that the entropy change for a particle in the given system is $-2.51 \times 10^{-24}$ J/K particle.

8 0

3 years ago

I will brainly <br> And 5 star rate

Alex777 [14]

The answer is Agree :)

6 0

3 years ago

Read 2 more answers

What was the half-life of a new isotope?

REY [17]

The half-life of any substance is the amount of time taken for half of the original quantity of the substance present to decay. The half-life of a radioactive substance is characteristic to itself, and it may be millions of years long or it may be just a few seconds.

In order to determine the half-life of a substance, we simply use:
t(1/2) = ln(2) / λ

Where λ is the decay constant for that specific isotope.

8 0

3 years ago