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wolverine [178]
3 years ago
9

What is one way to test whether an unknown solution is acidic or basic?

Chemistry
1 answer:
sertanlavr [38]3 years ago
4 0

Answer: There are several ways. The first that comes to mind is a pH meter. A pH electrode Is lowered into the solution, and (Assuming) the pH Meter has been properly calibrated, and the temperature of the solution is set to the calibration of the Meter, the pH can be read directly from an analogue scale or digital readout. Below 7 is acidic, 7 is Neutral, (like Pure Water), and over 7 is Alkaline, or Basic.

A useful, but less accurate method is the use of any number of “pH Indicator Solutions”, which are essentially a type of various colored dyes that change color within differing pH ranges. Usually, if the pH is unknown, a small amount of solution is removed from the container and tested separately - in a “well plate”, or similar method.

These types of dyes, or Indicator Solutions, can be dried upon strips of “pH indicator Paper”, which, depending upon the type can be very useful when carrying out more precisely arrived at pH tests like Titration.

Just to see if a solution is “Acid” or “Base”, Litmus paper is used; “a Red color shows Acidity, and a Blue color, a Base”; ergo, “An Acid Solution will turn Litmus Paper, Red”.

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Liter measures liquid- so a measuring cup
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What is the temperature (in K) of a sample of nitrogen with an root-
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Which organelle’s function is NOT correct?
Scorpion4ik [409]
The answer is the last one, “The cell membrane is the only source of support and structure in plant and animal cells.” That is false because plant cells have a cell wall and cell membrane while animal cells only have a cell membrane.

Hope this helps:)
5 0
3 years ago
How many moles are in 12 liters of Cl2?
RoseWind [281]

Answer:

\boxed {\boxed {\sf 0.54 \ mol \ Cl_2}}

Explanation:

A mole is any quantity of a substance that contains 6.02 × 10²³ particles. At standard temperature and pressure, or STP, 1 mole of as is equal to 22.4 liters. This is true for any gas, regardless of the specific kind.

Although it is not specified, we can assume this gas is at STP. Let's set up a ratio using this information: 22.4 L/mol

\frac {22.4 \ L \ Cl_2}{1 \ mol \ Cl_2}

Multiply by the given number of liters: 12

12 \ L \ Cl_2 *\frac {22.4 \ L \ Cl_2}{1 \ mol \ Cl_2}

Flip the ratio so the liters of chlorine cancel.

12 \ L \ Cl_2 * \frac {1 \ mol \ Cl_2}{22.4 \ L \ Cl_2}

12  * \frac {1 \ mol \ Cl_2}{22.4 }

\frac {12}{22.4 }  \ mol \ Cl_2

0.53571428571 \ mol \ Cl_2

The original measurement of liters has 2 significant figures, so our answer must have the same.

For the number we found, that is the hundredth place.

  • 0.53<u>5</u>71428571

The 5 in the thousandth place tells us to round the 3 up to a 4.

0.54 \ mol \ Cl_2

12 liters of chlorine gas at STP is approximately <u>0.54 moles of chlorine gas.</u>

8 0
3 years ago
You have 26.7 mL of 0.061 mol/L aqueous potassium hydroxide (KOH(aq)) in a conical flask. In a burette
Natasha2012 [34]

Answer:

9.47 mL

Explanation:

The reaction that takes place is:

  • 2KOH + H₂SO₄ → K₂SO₄ + 2H₂O

First we <u>calculate how many KOH moles reacted</u>, using <em>the given concentration and volume of KOH solution</em>:

  • 0.061 mol/L = 0.061 mmol/mL
  • 0.061 mmol/mL * 26.7 mL = 1.6287 mmol KOH

Then we <u>convert KOH moles into H₂SO₄ moles</u>, using the <em>stoichiometric coefficients</em>:

  • 1.6287 mmol KOH * \frac{1mmolH_2SO_4}{2mmolKOH} = 0.8144 mmol H₂SO₄

Finally we <u>calculate the required volume of the H₂SO₄ solution</u>, using<em> the number of moles and given concentration</em>:

  • 0.8144 mmol ÷ 0.086 mmol/mL = 9.47 mL
5 0
3 years ago
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