it has less tightly bound electrons, is able to lose electron easily as compare to metal B at it has 4 unpaired electron in 3d sub-shell.
Answer:
There are 3 significant figures in 675000
Explanation:
The rules for significant figures:
- Non zero digit (from 1 upward) are always significant
- Trailing zero are not significant
- but zero in the presence of decimal are significant
In this case, the trailing zeros are not significant thus only the first 3 non zero digit are significant.
2C4H10 + 13O2 -> 8CO2 + 10H2O
NH₃:
N = 8*10²²
NA = 6.02*10²³
n = N/NA = 8*10²²/6.02*10²³ ≈ 1.33*10⁻¹=0.133mol
O₂:
N=7*10²²
NA = 6.02*10²³
n = N/NA = 7*10²²/6.02*10²³ = 1.16*10⁻¹=0.116mol
4NH₃ <span>+ 3O</span>₂ ⇒<span> 2N</span>₂<span> + 6H</span>₂<span>O
</span>4mol : 3mol : 2mol
0.133mol : 0.116mol : 0,0665mol
limiting reactant
N₂:
n = 0.0665mol
M = 28g/mol
m = n*M = 0.0665mol*28g/mol = <u>1,862g</u>
The answer is <span>commensalism</span>
