3(d+2)-12 = d-2
3d +6 -12 = d - 2
3d-d = 12 - 6 - 2
2d = 4
d = 2
Answer:
2). As x-> -∞, f(x)->∞
As x-> ∞, f(x)-> -∞
5). As x-> -∞, f(x)-> -∞
As x-> ∞, f(x)-> ∞
3). As x-> -∞, f(x)-> -∞
As x-> ∞, f(x)-> ∞
6). As x-> -∞, f(x)-> ∞
As x-> ∞, f(x)-> ∞
Step-by-step explanation:
I just watched a quick video so you can't completely trust me, but i tried my best. Hopefully someone more trustworthy for this comes in.
We can proceed in solving the problem since all information are given such as 2*4*5costheta.
we have a=4, b=5, and C=theta
let us solve for "c" using Pythagorean
c²=a²+b²
c²=4²+5²
c=6.4
Solving for theta or C
c²=a²+b²-2abcosC
6.4²=4²+5²-2*4*5*cosC
C=90
102. Take the largest number and subtract the lowest. Brainliest please?
