Answer : The percent-by-mass concentration of acetic acid is, 5.15 %
Explanation : Given,
Mass of acetic acid = 51.80 g
Density of solution = 1.005 g/ml
Volume of solution = 1.000 L = 1000 ml (1 L = 1000 ml)
First we have to calculate the mass of solution.
Now we have to calculate the percent-by-mass concentration of acetic acid.
Now put all the given values in this formula, we get:
Therefore, the percent-by-mass concentration of acetic acid is, 5.15 %
<span> The temperature of the water in both beakers is greater than 8 °C
This is because since the water passes on heat to the spheres, that means they are at a higher temperature then the spheres. if they were at a lower temp. The spheres would pass on heat to the water.
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Answer:
1.17 grams of HCl can neutralize 2.7 grams sodium bicarbonate
Explanation:
Step 1: Data given
Mass of sodium bicarbonate = 2.7 grams
Step 2: The balanced equation
HCl + NaHCO3 ⇔ NaCl + H2O + CO2
Step 3: Calculate moles NaHCO3
moles NaHCO3 =2.7 g / 84 g/mol= 0.032 moles
Step 4: Calculate moles HCl
For 1 mol NaHCO3 we need 1 mol HCl
For 0.032 moles NaHCO3 = 0.032 moles HCl
Step 5: Calculate mass HCl
Mass HCl = moles HCl * molar mass HCl
mass HCl = 0.032 * 36.46 g/mol= 1.17 grams
1.17 grams of HCl can neutralize 2.7 grams sodium bicarbonate
The arrangement of electron pairs around CH4 and NH3, According to the VSEPR model is the same, because in each case there are the same number of electron pairs around the central atom. So the NH3 and CH4 arrangement of electron pairs is the same because in each case there are the same number of electron pairs around the central atom.
