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Anon25 [30]
3 years ago
10

Find the distance between the points A and B given below.

Mathematics
1 answer:
GalinKa [24]3 years ago
5 0

Answer:

use formula

Step-by-step explanation:

distance between the points A and B=

√((x2-x1)²+(y2-y1)²)

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It has been proven that of all line segments drawn from a given point not on it, the perpendicular line segment is the shortest.

<h3>How to prove a Line Segment?</h3>

We know that in a triangle if one angle is 90 degrees, then the other angles have to be acute.

Let us take a line l and from point P as shown in the attached file, that is, not on line l, draw two line segments PN and PM. Let PN be perpendicular to line l and PM is drawn at some other angle.

In ΔPNM, ∠N = 90°

∠P + ∠N + ∠M = 180° (Angle sum property of a triangle)

∠P + ∠M = 90°

Clearly, ∠M is an acute angle.

Thus; ∠M < ∠N

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Similarly, by drawing different line segments from P to l, it can be proved that PN is smaller in comparison to all of them. Therefore, it can be observed that of all line segments drawn from a given point not on it, the perpendicular line segment is the shortest.

Read more about Line segment at; brainly.com/question/2437195

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kondor19780726 [428]

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