Answer:
Rutherford bombarded aluminum foil with beam of light known as alpha particles. The mass of this alpha particle is equivalent to helium atom.
Explanation:
Rutherford bombarded aluminum foil with beam of light known as alpha particles. The mass of this alpha particle is equivalent to helium atom.
When this alpha particles were made to strike the aluminum foil, some passed through the foil, some were reflected and speed others changed.
The ones reflected encountered heavier particle known as the nucleus, preventing them from passing through it. The whole observations indicated that atom is not is uniformly charged sphere as proposed by J.J Thomson.
Rutherford proposed new model known as the Planetary model of atom, which described atom as containing a nucleus which is revolved by electron, just like planets revolve round the sun. And this nucleus contains opposite charge to electron which is proton, to balance the motion.
Answer: momentum = 6kgm/s
Explanation:
given that the baseball pitcher is at stationary position, his velocity will be equal to zero. If velocity is zero, his linear momentum will therefore equal to zero.
Linear momentum is the product of mass and velocity. Given that the baseball has
Mass M = 0.15 kg
Velocity V = 40 m/s
Momentum = MV
Momentum = 0.15 × 40 = 6 kgm/s
The magnification <u>is 31.16.</u>
Magnification is the process of increasing the apparent size of something rather than its physical size. This increase is quantified by a calculated number, also called the "factor". If this number is less than 1, it means size reduction, sometimes called size reduction or reduction.
u = -19.3
f = -18.7 cm.
m = f/f-u
= -18.7/-18.7 +19.3
<u>= 31.16</u>
The term magnification refers to the size of the image produced by the lens compared to the size of the object. For lenses: Magnification "m" is the ratio of image height to object height. The magnification of a lens is defined as the ratio of image height to object height. It is also given by image distance and object distance. equal to the ratio of image distance to object distance.
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The correct expression for the maximum speed of the object during its motion is
.
<h3>
Maximum speed of the object</h3>
The maximum speed of the object is determined using the following formulas;
v(max) = Aω
where;
- A is the amplitude of the motion
- ω is angular speed
The maximum speed of the object can also be obtained from the maximum net force on the object,
F = ma
where;
- F is the maximum net force
- a is the acceleration
- m is mass of the object
F = m(v/t)
mv = Ft
v = Ft/m
Thus, the correct expression for the maximum speed of the object during its motion is
.
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