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Darya [45]
2 years ago
15

As a global society with many political demarcations, what is the best way to preserve resources that are held in common? What s

pecial problems does this kind of preservation entail?
Engineering
1 answer:
MariettaO [177]2 years ago
8 0

Answer:

kindly check the explanation section.

Explanation:

In order to be able to preserve resources that are common there is need for each countries in the world to agree and cooperate. Also, policies should be set and made the standard for all countries involved. The developed countries should come together with developing measures to make sure that there is mutual agreements between these countries to preserve common resources. For instance, the most common resource is the Ozone layer, the industrialization in developed countries causes the depletion of ozone.

The main problem that the kind of preservation entails is how to get money for countries that are not rich enough to follow the agreed laydown rules. Other problems are: differences in economies and each countries have their own ways of regulating and preserving resources.

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Sed is a multipurpose tool that combines the work of several filters. sed performs noninteractive operations on a data stream. s
timama [110]

Answer:

The answer is True.

Explanation:

SED is a command in UNIX for stream editors that parses and transforms text, using a simple, compact programming language. So the answer is TRUE that sed is a multipurpose tool that combines the work of several filters and performs noninteractive operations on a data stream. sed has a host of features that allow you ti select lines and run instructions on them.

6 0
3 years ago
Calculate the value of ni for gallium arsenide (GaAs) at T = 300 K. The constant B = 3. 56 times 1014 9cm -3 K-3/2) and the band
meriva

This question is incomplete, the complete question is;

Calculate the value of ni for gallium arsenide (GaAs) at T = 300 K.

The constant B = 3.56×10¹⁴ (cm⁻³ K^-3/2) and the bandgap voltage E = 1.42eV.

Answer: the value of ni for gallium arsenide (GaAs) is 2.1837 × 10⁶ cm⁻³

Explanation:

Given that;

T = 300k

B = 3.56×10¹⁴ (cm⁻³ K^-3/2)

Eg = 1.42 eV

we know that, the value of Boltzmann constant k = 8.617×10⁻⁵ eV/K

so to find the ni for gallium arsenide;

ni = B×T^(3/2) e^ ( -Eg/2kT)

we substitute

ni = (3.56×10¹⁴)(300^3/2) e^ ( -1.42 / (2× 8.617×10⁻⁵ 300))

ni =  (3.56×10¹⁴)(5196.1524)e^-27.4651

ni = (3.56×10¹⁴)(5196.1524)(1.1805×10⁻¹²)

ni = 2.1837 × 10⁶ cm⁻³

Therefore the value of ni for gallium arsenide (GaAs) is 2.1837 × 10⁶ cm⁻³

4 0
3 years ago
The housing for a certain machinery product is made of two components, both aluminum castings. The larger component has the shap
Dmitry_Shevchenko [17]

Answer:

The pouring of the molten metal during casting is done very slowly hence the molten metal froze before reaching all parts of the mould cavity. also the early freezing can occur if the temperature of the molten metal was lower than the required temperature for casting

Explanation:

since the same components are being casted at other foundries and they don't have the defects ,

Hence the reason for the defects experienced by these components can be caused when the pouring of the molten metal during casting is done very slowly hence the molten metal froze before reaching all parts of the mould cavity. also the early freezing can occur if the temperature of the molten metal was lower than the required temperature for casting .

8 0
3 years ago
Given the following MATLAB statement: ( 3 + 2 ) / 5 * 4 + 5 ^ 2 In what order will these operations be done?
Andrei [34K]

Answer:

first is the parentheses, (3+2)=5 next is the exponent 5^2=25, next is the division 5 / 5 = 1, then the multiplication 4*1=4 and then you add 4+25=29. so the answer is 29.

7 0
3 years ago
A cylindrical 1045 steel bar is subjected to repeated compression-tension stress cycling along its axis. If the load amplitude i
Gre4nikov [31]

Answer:

13.4 mm

Explanation:

Given data :

Load amplitude ( F )  = 22,000 N

factor of safety ( N )= 2.0

Take ( Fatigue limit stress amplitude for this alloy ) б = 310 MPa

<u>calculate the minimum allowable bar diameter to ensure that fatigue failure will not occur</u>

minimum allowable bar diameter = 13.4 * 10^-3 m ≈ 13.4 mm

<em>attached below is a detailed solution</em>

3 0
2 years ago
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