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tigry1 [53]
3 years ago
14

You have designed a bone plate that is manufactured via rolling under cold working conditions, and tests show good biocompatibil

ity results for the device. The Manufacturing Department has put in a request to change the processing method to rolling under hot working conditions, in an effort to reduce the total manufacturing cost. Since the material from which the device is fabricated will not change, do you need to rerun the biocompatibility tests? Why or why not? (10 points)
Engineering
1 answer:
kompoz [17]3 years ago
8 0

Answer:

No need to rerun the biocompatibility tests

Explanation:

There is no need to regenerate because we use the same material and hot work results to eliminate or reduce chemical-symmetry due to enhanced dispersion at higher temperatures and may reduce size during deformation and this has a positive impact on biochemical reliability.

so No need to rerun the biocompatibility tests

You might be interested in
Prompt the user to enter five numbers, being five people's weights. Store the numbers in an array of doubles. Output the array's
atroni [7]

Answer:

See below in the explanation section the Matlab script to solve the problem.

Explanation:

prompt='enter the first weight w1:  ';

w1=input(prompt);

wd1=double(w1);

prompt='enter the second weight w2:  ';

w2=input(prompt);

wd2=double(w2);

prompt='enter the third weight w3:  ';

w3=input(prompt);

wd3=double(w3);

prompt='enter the fourth weight w4:  ';

w4=input(prompt);

wd4=double(w4);

prompt='enter the first weight w5:  ';

w5=input(prompt);

wd5=double(w5);

x=[wd1 wd2 wd3 wd4 wd5]

format short

6 0
3 years ago
Which is an alloy made up of iron and carbon and has high compressive and tensile strength?
Digiron [165]

Answer: Steel is an alloy of iron with typically a few percent of carbon to improve its strength and fracture resistance compared to iron. Many other additional elements may be present or added. Stainless steels that are corrosion and oxidation resistant need typically an additional 11% chromium.

Explanation:

3 0
3 years ago
The solid cylinders AB and BC are bonded together at B and are attached to fixed supports at A and C. The modulus of rigidity is
romanna [79]

Answer:

a) 0.697*10³ lb.in

b) 6.352 ksi

Explanation:

a)

For cylinder AB:

Let Length of AB = 12 in

c=\frac{1}{2}d=\frac{1}{2} *1.1=0.55in\\ J=\frac{\pi c^4}{2}=\frac{\pi}{2}0.55^4=0.1437\ in^4\\

\phi_B=\frac{T_{AB}L}{GJ}=\frac{T_{AB}*12}{3.3*10^6*0.1437}  =2.53*10^{-5}T_{AB}

For cylinder BC:

Let Length of BC = 18 in

c=\frac{1}{2}d=\frac{1}{2} *2.2=1.1in\\ J=\frac{\pi c^4}{2}=\frac{\pi}{2}1.1^4=2.2998\ in^4\\

\phi_B=\frac{T_{BC}L}{GJ}=\frac{T_{BC}*18}{5.9*10^6*2.2998}  =1.3266*10^{-6}T_{BC}

2.53*10^{-5}T_{AB}=1.3266*10^{-6}T_{BC}\\T_{BC}=19.0717T_{AB}

T_{AB}+T_{BC}-T=0\\T_{AB}+T_{BC}=T\\T_{AB}+T_{BC}=14*10^3\ lb.in\\but\ T_{BC}=19.0717T_{AB}\\T_{AB}+19.0717T_{AB}=14*10^3\\20.0717T_{AB}=14*10^3\\T_{AB}=0.697*10^3\ lb.in\\T_{BC}=13.302*10^3\ lb.in

b) Maximum shear stress in BC

\tau_{BC}=\frac{T_{BC}}{J}c=13.302*10^3*1.1/2.2998=6.352\ ksi

Maximum shear stress in AB

\tau_{AB}=\frac{T_{AB}}{J}c=0.697*10^3*0.55/0.1437=2.667\ ksi

8 0
3 years ago
A certain piece of property is assessed at $150,000. If the tax rate is $2.50 per $100, what is the tax on this property?
stiks02 [169]

Answer:

The tax on this property is 3750 dollars

Explanation:

Given

Tax on per $100 is $2.50

Tax on every $1 is \frac{2.5}{100} = 0.025 dollars

Tax on property of value $150,000 is

150,000 * 0.025 = 3750 dollars

The tax on this property is 3750 dollars

7 0
3 years ago
Write a program that removes all spaces from the given input. You may assume that the input string will not exceed 50 characters
GrogVix [38]

Answer:

Program that removes all spaces from the given input

Explanation:

// An efficient Java program to remove all spaces  

// from a string  

class GFG  

{  

 

// Function to remove all spaces  

// from a given string  

static int removeSpaces(char []str)  

{  

   // To keep track of non-space character count  

   int count = 0;  

 

   // Traverse the given string.  

   // If current character  

   // is not space, then place  

   // it at index 'count++'  

   for (int i = 0; i<str.length; i++)  

       if (str[i] != ' ')  

           str[count++] = str[i]; // here count is  

                                   // incremented  

         

   return count;  

}  

 

// Driver code  

public static void main(String[] args)  

{  

   char str[] = "g eeks for ge eeks ".toCharArray();  

   int i = removeSpaces(str);  

   System.out.println(String.valueOf(str).subSequence(0, i));  

}  

}  

5 0
3 years ago
Read 2 more answers
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