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stira [4]
3 years ago
15

Whats the awnser? i cant find it and i need it asap! anyone i will crown you the brainleist!

Chemistry
1 answer:
Sauron [17]3 years ago
8 0
You spelled answer wrong
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which components of an endothermic reaction have a higher heat content?-reactants-products-reaction vessel-water
lana66690 [7]
Please, observe that it is not right to say that a substance content heat.

Heat is not something that a body or substance content. Heat is the transmission of energy due to difference of temperatures.

An endothermic reactions is that where the reactants abosorb energy from the surroundings to occur. The products, then, will be higher in energy than the reactants while the surroundings get colder.
9 0
3 years ago
Read 2 more answers
A 3.452 g sample containing an unknown amount of a Ce(IV) salt is dissolved in 250.0-mL of 1 M H2SO4. A 25.00 mL aliquot is anal
SOVA2 [1]

Answer:

1,812 wt%

Explanation:

The reactions for this titration are:

2Ce⁴⁺ + 3I⁻ → 2Ce³⁺ + I₃⁻

I₃⁻ + 2S₂O₃⁻ → 3I⁻ + S₄O₆²⁻

The moles in the end point of S₂O₃⁻ are:

0,01302L×0,03428M Na₂S₂O₃ = 4,463x10⁻⁴ moles of S₂O₃⁻. As 2 moles of S₂O₃⁻ react with 1 mole of I₃⁻, the moles of I₃⁻ are:

4,463x10⁻⁴ moles of S₂O₃⁻×\frac{1molI_{3}^-}{2molS_{2}O_{3}^-} = 2,2315x10⁻⁴ moles of I₃⁻

As 2 moles of Ce⁴⁺ produce 1 mole of I₃⁻, the moles of Ce⁴⁺ are:

2,2315x10⁻⁴ moles of I₃⁻×\frac{2molCe^{4+}}{1molI_{3}^-} = 4,463x10⁻⁴ moles of Ce(IV). These moles are:

4,463x10⁻⁴ moles of Ce(IV)×\frac{140,116g}{1mol} = <em>0,0625 g of Ce(IV)</em>

As the sample has a 3,452g, the weight percent is:

0,0625g of Ce(IV) / 3,452g × 100 = <em>1,812 wt%</em>

I hope it helps!

5 0
3 years ago
Which elements are<br> considered "Noble Metals"?
Lisa [10]

Answer:

ruthenium (Ru), rhodium (Rh), palladium (Pd), osmium (Os), iridium (Ir), platinum (Pt), gold (Au), silver (Ag).

Explanation:

7 0
2 years ago
What is the term for the number of protons in the nucleus of each atom of an element?
xxTIMURxx [149]

Answer:

atomic number

Explanation:

atomic number is the number of protons

5 0
1 year ago
Consider the resonance structures of formate. the first lewis structure of formate has a central carbon atom. a hydrogen atom an
OleMash [197]
So,

Formate has a resonating double bond.

In molecular orbital theory, the resonating electrons are actually delocalized and are shared between the two oxygens.  So the carbon-oxygen bonds can be described as 1.5-bonds (option B).  I'm not sure if option C is correct, however, because the likelihood of both delocalized electrons being in the area of one oxygen atom is less than 50%.<span />
6 0
3 years ago
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