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NemiM [27]
2 years ago
9

Please help me please

Mathematics
2 answers:
myrzilka [38]2 years ago
8 0

Answer:

  • B. y = -4/3x + 22

Step-by-step explanation:

Parallel lines have the same slope.

<u>Use the given point (6, 14) and point-slope form:</u>

  • y - 14 = -4/3(x - 6)
  • y = -4/3x + 8 + 14
  • y = -4/3x + 22

Correct choice is B

Dennis_Churaev [7]2 years ago
7 0

Answer:

Solution given:

y=-4/3×x-1.......(1)

comparing above equation with y=mx+c

slope of line 1 is

m=-4/3

since the another line is parallel

slope is equal

m=m1=-4/3.

since it passes through (6,14)

we have

equation of a line is:

(y-y1)=m1(x-x1)

(y-14)=-4/3(x-6)

y=-4/3×x+4/3×6+14

y=-4/3×x+8+14

y=-4/3×x+22.

your option is b.y=-4/3×x+22.

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Answer: x = 15.035677095729 approximately

Round this however you need to.

=================================================

Explanation:

I'm assuming you want to find the value of x, which your diagram is showing to be the length of segment QR.

If so, then we'll need to find the measure of angle Q first. Using the law of sines, we get the following:

sin(Q)/q = sin(R)/r

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sin(Q) = 13*sin(85)/19

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Q = arcsin(0.6816068987) ... or ... Q = 180-arcsin(0.6816068987)

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----------------

Now if Q = 42.9693397461 approximately, then angle P is

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P = 180-42.9693397461-85

P = 52.0306602539

Similarly, if Q = 137.0306602539 approximately, then,

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P = 180-137.0306602539-85

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A negative angle is not possible, so we'll ignore Q = 137.0306602539

----------------

The only possible value of angle P is approximately P = 52.0306602539

Let's apply the law of sines again to find side p, aka segment QR

sin(P)/p = sin(R)/r

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sin(52.0306602539)/x = sin(85)/19

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19*sin(52.0306602539)/sin(85) = x

x = 15.035677095729

This value is approximate.

Round this value however you need to.

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