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Brrunno [24]
3 years ago
15

A 35.6 g sample of ethanol (c2h5oh) is burned in a bomb calorimeter, according to the following reaction. if the temperature ros

e from 35.0 to 76.0°c and the heat capacity of the calorimeter is 23.3 kj/°c, what is the value of δh°rxn? the molar mass of ethanol is 46.07 g/mol.
Chemistry
1 answer:
abruzzese [7]3 years ago
6 0
Answer is: molar heat of reaction of combustion of ethanol is 1237.435 kJ/mol.
m(C₂H₅OH) = 35.6 g.
n(C₂H₅OH) = m(C₂H₅OH) ÷ M(C₂H₅OH).
n(C₂H₅OH) = 35.6 g ÷ 46.07 g/mol.
n(C₂H₅OH) = 0.772 mol.
ΔT = 76.0°C - 35.0°C = 41°C.
Q = ΔT · C.
Q = 41°C · 23.3 kJ/°C.
Q = 955.3 kJ.
ΔH = Q / n(C₂H₅OH).
ΔH = 955.3 kJ / 0.772 mol.
ΔH = 1237.435 kJ/mol.
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5 0
1 year ago
A buffer solution contains 0.496 M hydrocyanic acid and 0.399 M sodium cyanide . If 0.0461 moles of sodium hydroxide are added t
pochemuha

Answer : The pH of the solution is, 9.63

Explanation : Given,

The dissociation constant for HCN = pK_a=9.31

First we have to calculate the moles of HCN and NaCN.

\text{Moles of HCN}=\text{Concentration of HCN}\times \text{Volume of solution}=0.496M\times 0.225L=0.1116mole

and,

\text{Moles of NaCN}=\text{Concentration of NaCN}\times \text{Volume of solution}=0.399M\times 0.225L=0.08978mole

The balanced chemical reaction is:

                          HCN+NaOH\rightarrow NaCN+H_2O

Initial moles     0.1116       0.0461     0.08978

At eqm.       (0.1116-0.0461)    0       (0.08978+0.0461)

                        0.0655                       0.1359

Now we have to calculate the pH of the solution.

Using Henderson Hesselbach equation :

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4 0
3 years ago
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8 0
2 years ago
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7 0
2 years ago
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C    15.8       15.8/12         = 1.32         1.32/1.32 ≈ 1
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The molecular formula would be K2C2O3.
4 0
3 years ago
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