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OLEGan [10]
3 years ago
5

Determine the values of x and y.

Mathematics
1 answer:
BaLLatris [955]3 years ago
5 0

Answer:

answer is d please follow me I hope it will help you

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3 years ago
Place the indicated product in the proper location on the grid. (4x^3+7y^3 z^ 4) ^2
ella [17]

Answer:

16x^{6} +56x^{3}y^{3} z^{4} +49y^{6} z^{8} \\

Step-by-step explanation:

To solve this type of problems first need to review some laws of exponents:

When you are multiplying the same base, you need to add the exponents.

x^{2} +x^{8}  = x^{2+8}  = x^{10}

When you are raising a base with power to another power, you should keep the base and multiply the exponents:

(x^{2} y^{5})^3 = x^{2*3} y^{5*3} = x^{6} y^{15}

Now for the expression (4x^{3} + 7y^{3} z^{4} )^2

Write the multiplying factors:

(4x^{3} + 7y^{3} z^{4} )(4x^{3} + 7y^{3} z^{4} )

Multiply the term 4x^{3}

(4x^{3} + 7y^{3} z^{4} )(4x^{3} + 7y^{3} z^{4} ) = 16x^{3+3} + 28x^3y^{3} z^{4}

Then multiply the term 7y^{3}z^{4}

(4x^{3} + 7y^{3} z^{4} )(4x^{3} + 7y^{3} z^{4} ) = 16x^{3+3} + 28x^3y^{3} z^{4}\\\\+ 28x^3y^{3} z^{4} + 49y^{3+3} z^{4+4}

Simplify the exponents:

(4x^{3} + 7y^{3} z^{4} )(4x^{3} + 7y^{3} z^{4} ) = 16x^{6} + 28x^3y^{3} z^{4}\\\\+ 28x^3y^{3} z^{4} + 49y^{6} z^{8}

Add like terms:

= 16x^{6} + 56x^3y^{3} z^{4} + 49y^{6} z^{8}

5 0
3 years ago
Someone please help me with this
Ket [755]

Answer:

19. yes 20.no 21. yes 22.no

Step-by-step explanation:

3 0
3 years ago
The pyramid shown has a square base that is 24 centimeters on each side. The slant height is 16 centimeters. What is the lateral
Aleksandr-060686 [28]
Check the picture below.

the "lateral" area, or "sides" area, is just the area of all the four triangular faces, and it doesn't include the bottom or base of the pyramid.

however, notice, each triangular face is really just a triangle with a base of 24, and a height of 16.

\bf \left[\frac{1}{2}(\stackrel{b}{24})(\stackrel{h}{16}) \right]+\left[\frac{1}{2}(\stackrel{b}{24})(\stackrel{h}{16}) \right]+\left[\frac{1}{2}(\stackrel{b}{24})(\stackrel{h}{16}) \right]+\left[\frac{1}{2}(\stackrel{b}{24})(\stackrel{h}{16}) \right]&#10;\\\\\\&#10;\textit{or just }\qquad 4\left[\frac{1}{2}(\stackrel{b}{24})(\stackrel{h}{16}) \right]\impliedby \textit{lateral area of the pyramid}

6 0
3 years ago
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