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alekssr [168]
3 years ago
13

Betty is sitting on of her surfboard out in the ocean. She is waiting for the perfect wave to come along so she can ride it in t

o shore. As she waits, she notices that the waves roll by in patterns, or sets.
As Betty waits, she counts the number of waves that pass her during a 10-second period; she counts just 1. She estimates that the distance between crests is 6 meters. Betty sees the perfect wave and begins paddling. She pushes herself up, stands on the surfboard and rides the wave all the way in to shore, a distance of about 60 meters. It takes her about 10 seconds to ride the wave in. Use two methods to calculate the speed of the wave based on the information presented. Are they the same? Explain how you got your answers.
Physics
1 answer:
Ymorist [56]3 years ago
8 0

Answer:

No they are not the same.

Explanation:

S=d/t Speed equals distance divided by time. Leah's wave took 10 seconds, and the distance was 6 meters.

6/10=.6

Betty's wave took 10 seconds, but the distance was 60 meters this time.

60/10=6

We know that 6 and .6 are not the same numbers, so we can see that the waves aren't the same.

I hope this helps!!

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Answer:

the correct answer is c) 23 g

Explanation:

The heat lost by the runner has two parts: the heat absorbed by sweat in evaporation and the heat given off by the body

     Q_lost = - Q_absorbed

     

The latent heat is

      Q_absorbed = m L

The heat given by the body

      Q_lost = M c_{e} ΔT

       

where m is the mass of sweat and M is the mass of the body

       m L = M c_{e} ΔT

        m = M c_{e} ΔT / L

let's replace

        m = 90  3.500  1.8 / 2.42 10⁶

 

        m = 0.2343 kg

reduced to grams

        m = 0.2342 kg (1000g / 1kg)

        m = 23.42 g

 the correct answer is c) 23 g

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that is your answer
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