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3 years ago

What is a Wave BEHAVIOR

Physics

2 answers:

kodGreya [7K]3 years ago

7 0

How light reflects across the electromagnetic spectrum thats all really. strech it out however you want to

tino4ka555 [31]3 years ago

3 0

Answer: a wave behavior is a Light waves across the electromagnetic spectrum behave in similar ways. When a light wave encounters an object, they are either transmitted, reflected, absorbed, refracted, polarized, diffracted, or scattered depending on the composition of the object and the wavelength of the light.

Explanation:

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A curent-carrying 2.0-cm long segment of wire is inside a long solenoid adius - 40 cm - 800 turns/m, current - 50 mA). The wire

klasskru [66]

Answer:

The value is $F_{max} = 12 \muN$

Explanation:

From the question we are told that

The length is $l = 2.0 \ cm = 0.02 \ m$

The radius of the the solenoid is $r =40 \ cm$

The number of turns per meter is $N = 800 \ turns / m$

The current through the solenoid is $I = 50 \ mA = 50*10^{-3} \ A$

The current through the segment is $I_s = 12 \ A$

Generally the magnetic force is mathematically represented as

$F = B * I_s l sin(\theta)$

At maximum $\theta = 90^o$

$F_{max} = B * I_s l$

Here B is the magnetic field is mathematically represented as

$B = \mu_o * N * I$

Here $\mu_o$ is the permeability of free space with value

$\mu_o = 4\pi * 10^{-7} N/A^2$

$B = 4\pi * 10^{-7} * 800 *50*10^{-3}$

=> $B = 5.0272 *10^{-5} \ T$

$F_{max} = 5.0272 *10^{-5} * 12 * 0.02$

$F_{max} = 1.2 *10^{-5}$

$F_{max} = 12 \muN$

4 0

3 years ago

If the torque required to loosen a nut that holds a wheel on a car has a magnitude of 55 n·m, what force must be exerted at the

erastova [34]

Either 175 N or 157 N depending upon how the value of 48Â° was measured from.
You didn't mention if the angle of 48Â° is from the lug wrench itself, or if it's from the normal to the lug wrench. So I'll solve for both cases and you'll need to select the desired answer.
Since we need a torque of 55 NÂ·m to loosen the nut and our lug wrench is 0.47 m long, that means that we need 55 NÂ·m / 0.47 m = 117 N of usefully applied force in order to loosen the nut. This figure will be used for both possible angles.
Ideally, the force will have a 0Â° degree difference from the normal and 100% of the force will be usefully applied. Any value greater than 0Â° will have the exerted force reduced by the cosine of the angle from the normal. Hence the term "cosine loss".
If the angle of 48Â° is from the normal to the lug wrench, the usefully applied power will be:
U = F*cos(48)
where
U = Useful force
F = Force applied
So solving for F and calculating gives:
U = F*cos(48)
U/cos(48) = F
117 N/0.669130606 = F
174.8537563 N = F
So 175 Newtons of force is required in this situation.
If the 48Â° is from the lug wrench itself, that means that the force is 90Â° - 48Â° = 42Â° from the normal. So doing the calculation again (this time from where we started plugging in values) we get
U/cos(42) = F
117/0.743144825 = F
157.4390294 = F
Or 157 Newtons is required for this case.

6 0

3 years ago

Two objects, one having twice the mass of the other, are initially at rest. Two forces, one twice as big as the other, act on th

Elodia [21]

Note: There is no image to take as a reference, so I'm assuming F2 directed to the right and F1 to the left, and F2=2F1

Answer:

$\displaystyle a=\frac{F}{3M}$

to the right

Explanation:

Net Force

When several forces are applied to a particle or a system of particles, the net force is the sum of them all, considering each force as a vector. As for the second Newton's law, the total force equals the product of the mass by the acceleration of the system:

$\vec F_n=m\cdot \vec a$

If the net force is zero, then the system of particles keeps at rest or at a constant velocity.

The system of particles described in the question consists of two objects of masses m1=M and m2, where

$m_2=2m_1=2M$

Two forces F1=F and F2 act individually on each object in opposite directions and

$F_2=2F_1=2F$

We don't get to see any image to know where the forces are applied to, so we'll assume F2 to the right and F1 to the left.

The net force of the system of particles is

$F_n=2F-F=F$

The mass of the system is

$m_t=m_1+m_2=3M$

Thus, the acceleration of the center of mass of the system is

$\displaystyle a=\frac{F}{3M}$

Since F2 is greater than F1, the direction of the acceleration is to the right.

Note: If the forces were opposite than assumed, the acceleration would be to the left

6 0

3 years ago

Help please....................

Marina86 [1]

Answer:

a. arranging from least to higher pressure exerted by object B ,D A, C

b object B exert maximum pressure on surface because pressure is indirectly proportional to the surface area from the above figure we can easily conclude that object a have least surface area so, it exert more pressure on surface.

c.object C exert minimum pressure on surface because pressure is indirectly proportional to the surface area from the above figure we can easily conclude that object a have large surface area so, it exert less pressure on surface.

Explanation:

7 0

3 years ago

The only two forces acting on a body have magnitudes of 20 N and 35 N and directions that differ by 80°. The resulting accelerat

pantera1 [17]

Answer:

b) 2.2 kg

Explanation:

Net force acting on an object is the sum of the two forces acting on the body.

The net force is calculated using the parallelogram law of vectors.

F = $\sqrt{{A^{2}} + B^{2}+2 A B cos \theta}$

Here A = 20 N , B = 35 N and θ =80°

Net Force = F = 43.22 N

Acceleration = a = 20 m/s/s

Since F = ma, m = F/a = 43.22 / 20 = 2.161 kg = 2.2 kg

8 0

3 years ago