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3 years ago

Help please....................

Physics

1 answer:

Marina86 [1]3 years ago

7 0

Answer:

a. arranging from least to higher pressure exerted by object B ,D A, C

b object B exert maximum pressure on surface because pressure is indirectly proportional to the surface area from the above figure we can easily conclude that object a have least surface area so, it exert more pressure on surface.

c.object C exert minimum pressure on surface because pressure is indirectly proportional to the surface area from the above figure we can easily conclude that object a have large surface area so, it exert less pressure on surface.

Explanation:

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A cell phone weighing 80 grams is flying through the air at 15 m/s what is the kinetic energy

hjlf

Answer:

$9\:\mathrm{J}$

Explanation:

Kinetic energy is given by the following equation:

$KE=\frac{1}{2}mv^2$ , where $m$ is mass in $\mathrm{kg}$ and $v$ is velocity in $\mathrm{m/s}$ .

Since the cell phone's mass is given in grams, we need to convert this into kilograms:

$80\:\mathrm{g}\cdot \frac{1\:\mathrm{kg}}{1000\:\mathrm{g}}=0.08\:\mathrm{kg}$ .

Therefore, the kinetic energy of the cell phone is:

$KE=\frac{1}{2}\cdot 0.08\cdot 15^2=\fbox{$9\:\mathrm{J}$}$ .

3 0

3 years ago

An electron is released a short distance above earth's surface. a second electron directly below it exerts an electrostatic forc

slamgirl [31]

The mass of an electron is 9.109 x 10⁻³¹ kg

The weight of the electron is (mass) x (g) = 8.926 x 10⁻³⁰ Newton

The charge on an electron is -1.602 x 10⁻¹⁹ Coulomb

The repelling force between the two electrons is (K · q₁ · q₂ / r²) =

(8.98755 x 10⁹ N-m²/C²) x (1.602 x 10⁻¹⁹ C)² / D²

In order for the bottom one to just exactly hold the top one up at a distance 'D', the repelling force has to be exactly equal to the weight of the upper electron.

8.926 x 10⁻³⁰ N = (8.98755 x 10⁹ N-m²/C²)·(1.602 x 10⁻¹⁹ C)² / D²

We have to solve THAT ugly mess for ' D '.

Clean up the units first:

Cancel the C² on the right side, then divide each side by Newton:

8.926 x 10⁻³⁰ = (8.98755 x 10⁹ m²) x (1.602 x 10⁻¹⁹)² / D²

Now, let's multiply both sides by (D² x 10²⁹) :

D² x 8.926 x 10⁻¹ = (8.98755 m²) x (1.602)²

Divide each side by (0.8926):

D² = (8.98755 x 1.602²) / (0.8926) meter²

D² = 25.84 m²

Take the square root of each side:

<em>D = 5.08 meters</em>

I am shocked, impressed, and amazed !

Are you shocked, impressed, or amazed ?

3 0

4 years ago

Si el periodo de oscilación de resorte es de 0,44 segundos cuando oscila atado a una masa de 2 Kg. ¿Cuál será el valor de la con

boyakko [2]

Answer:

i d k h b u lol I wish I knew it sorry

7 0

3 years ago

A water skier lets go of the tow rope upon leaving the end ofa

ANTONII [103]

Answer:

1.35m

Explanation:

At the highest point of the jump, the vertical speed of the skier should be 0. So the 13m/s speed is horizontal, this speed stays the same from the jumping point to the highest point. The 14m/s speed at jumping point is the combination of both vertical and horizontal speeds.

The vertical speed at the jumping point can be computed:

$v_v^2 + v_h^2 = v^2$

$v_v^2 + 13^2 = 14^2$

$v_v^2 = 196 - 169 = 27$

$v_v = \sqrt{27} = 5.2 m/s$

When the skier jumps to the its potential energy is converted to kinetic energy:

$E_p = E_k$

$mgh = mv_v^2/2$

where m is the skier mass and h is the vertical distance traveled, $v_v$ is the vertical velocity at jumping point, and h is the highest point.

Let g = 10m/s2

We can divide both sides of the equation by m:

$gh = v_v^2/2$

$h = \frac{v_v^2}{2g} = \frac{27}{2*10} = 1.35 m$

3 0

3 years ago

How does the theory of plate tectonics explain these similarities of location?

Nookie1986 [14]

<span>he theory states that Earth's outermost layer, the lithosphere, is broken into 7 large, rigid pieces called plates: the African, North American, South American, Eurasian, Australian, Antarctic, and Pacific plates. Several minor plates also exist, including the Arabian, Nazca, and Philippines plates. The plates are all moving in different directions and at different speeds</span>

7 0

3 years ago

Help please....................​

Help please....................