3 years ago

Describe what the difference between a series and a parallelogram arrangement

1 answer:

5 0

Answer:

In a series circuit, all components are connected end-to-end, forming a single path for current flow. In a parallel circuit, all components are connected across each other, forming exactly two sets of electrically common points.

Explanation:

You might be interested in

The fluorocarbon compound c2cl3f3 has a normal boiling point of 47.6°c. the specific heats of c2cl3f3(l) and c2cl3f3(g) are 0.91

myrzilka [38]

<span>To raise the liquid temperature to the point of boiling take 1231.776 joules of energy. To convert to a gas takes 5320.645 joules. To raise to 108 degrees Celsius takes 1456.848 joules. Total amount of energy needed (as heat) equals 8009.269 joules or 8.009 kj.</span>

7 0

3 years ago

Write a chemical equation that shows the release of hydroxide ions as each of these bases dissolves in water.

Zarrin [17]

KOH -------> K+ OH-
Ba(OH)2 ------> Ba+2. 2OH-

5 0

3 years ago

Name the four different types of Spheres belonging to Earth and give examples of Renewable resource and the Biotic factors that

madreJ [45]

Answer:

Everything in Earth's system can be placed into one of four major subsystems: land, water, living things, or air. These four subsystems are called "spheres." Specifically, they are the "lithosphere" (land), "hydrosphere" (water), "biosphere" (living things), and "atmosphere" (air).

Explanation:

4 0

3 years ago

If a gas is initially at a pressure of 9 atm, a volume of 21 liters, and a temperature of 253 K, and then the pressure is raised

alex41 [277]

Answer:

15.04 mL

Explanation:

Using Ideal gas equation for same mole of gas as

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

Given ,

V₁ = 21 L

V₂ = ?

P₁ = 9 atm

P₂ = 15 atm

T₁ = 253 K

T₂ = 302 K

Using above equation as:

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

$\frac {{9}\times {21}}{253}=\frac {{15}\times {V_2}}{302}$

Solving for V₂ , we get:

3 0

3 years ago

If 1.35 g of aluminum occupies 0.500 cm^3. what is the density of aluminum

qaws [65]

Answer:

2.7

Explanation:

Density= mass/volume

= 1.35/0.500

= 2.7

6 0

3 years ago