Question

Calculate the number of hydrogen atoms in 33.0 g CH4

Answer 1

Answer:

The number of hydrogen atoms is 4.96x10²⁴.

 

Explanation:

The number of atoms can be found with the following equation:

$n = N*\eta_{H}$

Where:

N: is the Avogadro's number = 6.022x10²³ atoms/mol

η: is the number of moles of hydrogen

n: is the number of hydrogen atoms

First, we need to find the number of hydrogen moles. The number of moles of CH₄ is:

$\eta_{CH_{4}} = \frac{m}{M}$

Where:

m: is the mass of methane = 33 g

M: is the molar mass of methane = 16.04 g/mol                      

$\eta_{CH_{4}} = \frac{33 g}{16.04 g/mol} = 2.06 mol$

Now, since we have 4 hydrogen atoms in 1 mol of methane, the number of moles of hydrogen is:

$\eta_{H} = 2.06\: mol\: CH_{4}*4 \frac{mol\: H}{mol \: CH_{4}} = 8.24 mol$

Hence, the number of hydrogen atoms is:

$n = N*\eta_{H} = 6.022 \cdot 10^{23} \: atoms/mol*8.24 mol = 4.96 \cdot 10^{24} atoms$

Therefore, the number of hydrogen atoms is 4.96x10²⁴.

I hope it helps you!