All categories

3 years ago

Find the volume of a cube of edge 20 cm

Mathematics

1 answer:

scZoUnD [109]3 years ago

8 0

Answer:

8000cm^3

Step-by-step explanation:

edge(a)= 20cm

volume of cube = a^3

= 20^3

=8000 cm^3

You might be interested in

-8z+(4.5)+3.5z+7y-1.5

bogdanovich [222]

Answer:

$\boxed{\sf{7y+3-4.5z}}$

Step-by-step explanation:

In order to combine like terms, you have to isolate x and y from one side of the equation.

$\sf{-8z+\left(4.5\right)+3.5z+7y-1.5}$

First, thing you do is remove parentheses.

$\Longrightarrow: \sf{-8z+4.5+3.5z+7y-1.5}$

Solve.

Then, you combine like terms.

$\Longrightarrow:\sf{-8z+3.5z+7y+4.5-1.5}$

Add/subtract the numbers from left to right.

-8z+3.5z=-4.5z

Rewrite the problem down.

$\Longrightarrow: \sf{-4.5z+7y+4.5-1.5}$

Solve.

4.5-1.5=3

$\Longrightarrow: \boxed{\sf{7y+3-4.5z}}$

Therefore, the correct answer is 7y+3-4.5z.

I hope this helps, let me know if you have any questions.

6 0

2 years ago

How can I get to 75 using 7 5 6 3

eduard

63+5+7=75

Hope this helps

4 0

3 years ago

Read 2 more answers

The area of a rectangle is 42 milimeter .The length is 7 milimeters. What is the perimter of rectangel?

Leni [432]

Answer:

6 millimeters

Step-by-step explanation:

A = L × W

A ÷ L = W

42 ÷ 7 = 6

8 0

3 years ago

Read 2 more answers

I need help ASAP with this question

Crazy boy [7]

Answer:

The answer is a.............................maybe........im not entirely sure

Step-by-step explanation:

3 0

3 years ago

PLZ HELL FAST WILL GIVE BRAINLIEST

Sauron [17]

${3x}^{2} - 5x = - 8 \\ {3x}^{2} - 5x + 8 = 0$

This equation has the next form:

${ax}^{2} + bx + c = 0$

To find if the equation has two complex solutions we have to check if the discriminant is negative, as follows:

${b}^{2} - 4ac \\ ( { - 5})^{2} - 4 \: . \: 3 \: . \: 8 = 25 - 96 = - 71 < 0$

Then, the first case has two complex solutions.

In the second case,

${2x}^{2} = 6x - 5 \\ {2x}^{2} - 6x + 5 = 0$

The discriminant in this case is:

$( { - 6})^{2} - 4 \: . \: 2 \: . \: 5 = 36 - 40 = - 4 < 0$

Then, the second case has two complex solutions.

In the third case,

$12x = {9x}^{2} + 4 \\ { - 9x}^{2} + 12x - 4 = 0$

The discriminant in this case is:

${12}^{2} - 4 \: . \: ( - 9) \: . \: ( - 4) = 144 - 144 = 0$

Then, the third case has two real solutions.

In the fourth case,

${ - x}^{2} - 10x = 34 \\ { - x}^{2} - 10x - 34 = 0$

The discriminant in this case is:

$( { - 10})^{2} - 4 \: . \: ( - 1) \: . \: ( - 34) = 100 - 136 = - 36 < 0$

Then, the fourth case has two complex solutions.

7 0

2 years ago

Read 2 more answers