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alina1380 [7]
3 years ago
10

A bag of 40 marbles had 8 white marbles.What is the probabilty of picking a white marble

Mathematics
1 answer:
weeeeeb [17]3 years ago
4 0

Answer: 8 / 48 or 1 / 6 (simplified).

Step-by-step explanation:

There are 48 marbles in the bag.

8 out of the 48 marbles are white, that's why the probability is 8/48 or 1/6.

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The temperature went from -16°F to 7°F. What was the change in temperature?
worty [1.4K]

Answer:

To find this out, we first need to see the change, is it a positive change or a negative change? Well in this case, as the temperature is increasing, we find that the change is positive. The next step we need to do, id that, how much was the change by, we can find this out by finding the absolute value of the difference of -16°F and 7°F

The absolute value means, the operations answer has to be positive, if not then it will become positive.

|-16°F -7°F|

=> |-23°F|

=> 23°F

If my answer helped, kindly mark me as the brainliest!!

Thank You!!

4 0
3 years ago
Can someone help me please
marysya [2.9K]

Answer:

A

Step-by-step explanation:

8 0
3 years ago
Complete the point-slope equation of the line through (-4,8) and (4,4)
notka56 [123]

Answer:

y-4=(-1/2)(x-4)

Step-by-step explanation:

Slope=(8-4)/(-4-4)=-4/8=-1/2

The equation of the line is y-4=(-1/2)(x-4)

4 0
3 years ago
Read 2 more answers
A random sample of 10 shipments of stick-on labels showed the following order sizes.10,520 56,910 52,454 17,902 25,914 56,607 21
sammy [17]

Answer:

Confidence Interval: (21596,46428)

Step-by-step explanation:

We are given the following data set:

10520, 56910, 52454, 17902, 25914, 56607, 21861, 25039, 25983, 46929

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{340119}{10} = 34011.9

Sum of squares of differences = 551869365.6 + 524322983.6 + 340111052.4 + 259528878 + 65575984.41 + 510538544 + 147644370.8 + 80512934.41 + 64463235.21 + 166851472.4 = 2711418821

S.D = \sqrt{\frac{2711418821}{9}} = 17357.09

Confidence interval:

\mu \pm t_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

t_{critical}\text{ at degree of freedom 9 and}~\alpha_{0.05} = \pm 2.2621

34011.9 \pm 2.2621(\frac{17357.09}{\sqrt{10}} ) = 34011.9 \pm 12416.20 = (21595.7,46428.1) \approx (21596,46428)

7 0
3 years ago
-3(-4b - 7n) use n = 8 and b = 2
gogolik [260]

The answer for your problem is 192

7 0
3 years ago
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