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3 years ago

What happens when stress builds up at faults?

Physics

2 answers:

snow_lady [41]3 years ago

4 0

AB just took the test

Harlamova29_29 [7]3 years ago

3 0

Answer:

The answer is D because when the faults move that is the tectonic plates moving. So earth quakes will be forming when the fault moves.

Explanation:

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A cup containing 200 g of hot water is taken off the stove placed on the kitchen table. Initially the water is at 75Degree C. bu

8090 [49]

Answer:

ΔH = -45.1872 kJ , where negative sign signifies heat loss.

Q = ΔH = -45.1872 kJ , where negative sign signifies heat loss.

S system = -0.141 kJ/K

S surroundings = 0.1536 kJ/K

S universe = -0.141 kJ/K + 0.1536 kJ/K = 0.0126 kJ/K

Explanation:

Given:

Cp = 4. 184 J/(mole. K)

T₁ = 75 ⁰C

T₂ = 21 ⁰C

Mass of water = 200 g = 0.2 kg

Since,

$\Delta H=m\times C\times (T_f-T_i)$

ΔH = 0.2*4.184*(21-75) kJ

ΔH = -45.1872 kJ , where negative sign signifies heat loss.

Since the process is at constant pressure

Q = ΔH = -45.1872 kJ , where negative sign signifies heat loss.

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

T₁ = 75 ⁰C = 348 .15 K

T₂ = 21 ⁰C = 294.15 K

The entropy of the water is given by:

S = m×Cp×ln(T₂ /T₁)

S = 0.2*4.184*ln(294.15/348.15)

S system = -0.141 kJ/K

The heat gain by surroundings

dQ = -Qreaction = 45.1872 kJ

The entropy change of surroundings is

S surr = dQ/T₂ = 45.1872/294 .15

S surr = 0.1536 kJ/K

The entropy of universe is the sum total of the entropy of the system and the surroundings and thus,

S universe = Ssys + Ssurr

S universe = -0.141 kJ/K + 0.1536 kJ/K = 0.0126 kJ/K

4 0

3 years ago

Which of the following equations illustrates the law of conservation of matter?

vagabundo [1.1K]

Answer:

I see no eaquations?

It should be matter=constant

3 0

3 years ago

How can oxygen enter the lungs?

Oksanka [162]

I just got this question not to long ago but to answer your question the primary function of the respiratory system is to exchange oxygen and carbon dioxide. Inhaled oxygen enters the lungs and reaches the alveoli. Oxygen passes quickly through this air-blood barrier into the blood in the capillaries. Similarly, carbon dioxide passes from the blood into the alveoli and is then exhaled.

6 0

4 years ago

A 0.300 kg potato is tied to a string with length 2.30 m , and the other end of the string is tied to a rigid support. The potat

alexdok [17]

Answer:

The speed of the potato at the lowest point is 6.714 m/s

The tension in the string is 8.82 N

Explanation:

We will use law of conservation of energy to find out the velocity

When the potato is at 2.30 m height, it will have potential energy and when the potato released it will go lowest point and it's potential energy will be convert into kinetic energy.

Potential energy = Kinetic energy

m×g×h = (1/2) m×v²

m stands for mass

g stands for gravitational constant

h stands for height

v stands for velocity

m×g×h = (1/2) m×v²

0.3×9.8×2.3 = (1/2) .3×v²

v² = 45.08

v = 6.714 m/s

The speed of the potato at lowest point is 6.714 m/s

Part B

The potato is in uniform circular motion so the acceleration is given by

a = v² / r

a stands for centripetal acceleration

According to Newton second law the acceleration is directly proportional to applied force and inversely proportional to the mass of object

So ∑ F = m × a

Two forces act on potato 1. weight due to gravitation in downward direction 2. tension in upward direction So the above equation become

Tension force - Force due to weight = m×a

T-m×g = m×a

centripetal acceleration formula =v²/r , r = l = length of the string

T = m ×(v²/l) + m×g

v = 6.714 m/s , l = 2.30 m , m = .3 kg Now put values in above equation

T = .3 × (6.714²/2.30) + .3 × 9.8

T = .3 ( 45.08/2.30) + 2.94

T = .3 (19.6) +2.94

T = 5.88 + 2.94

T = 8.82 N

The tension in the string is 8.82 N

5 0

3 years ago

A camera lens focuses on an

natka813 [3]

0.556cm height of image

5 0

2 years ago