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faust18 [17]
3 years ago
5

When does a circuit is said to be over loaded?​

Physics
2 answers:
Vlad [161]3 years ago
8 0

Answer:

Every electric circuit in a wiring system must be protected against overloads. A circuit overload occurs when the amount of current flowing through the circuit exceeds the rating of the protective devices. The amount of current flowing in a circuit is determined by the load -- or the "demand" -- for current.

Explanation:

Hope this helps :)

Yakvenalex [24]3 years ago
8 0

Answer:

a circuit is said to be overloaded when there is a fluctuation in flow of current,when large amount of current which increases kinetic energy thus increasing heat energy thus incresing temperature so circuit melts which may prove fatal.

Explanation:

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How many justified by Bohr model?
Dominik [7]

X-ray formation

Energy difference in the first ionization of the same group of elements

Differential linear emission spectra of different elements

Explanation:

The formation of x-ray, energy difference in the first ionization of the same group of elements and differential linear emission spectra of different elements can be justified by the Bohr model of the atom.

  • According to Neil Bohr, in an atom, the extranuclear part consists of electrons in specific spherical orbits around the nucleus.
  • Bohr's model explained the discrete lines in atomic spectrum of different elements.
  • Due to excitation of electrons, some rays are given off. Some of these are energetic like x-rays.
  • The energy difference between the first ionization of the same group of elements is a proof that electrons are in specific spherical orbits.
  • The higher the energy the level, the ease at which electrons can be removed and the lower the ionization energy.

Learn more:

Bohr model of the atom brainly.com/question/4986277

#learnwithBrainly

3 0
4 years ago
A spring with a spring constant of 165 N/m is attached to a 2.0 kg mass and set into motion.
marin [14]

Explanation:

We have,

Spring constant of the spring, k = 165 N/m

Mass, m = 2 kg

It is required to find the period of the mass-spring system. For the spring mass system, the period is given by :

T=2\pi \sqrt{\dfrac{m}{k} }\\\\T=2\pi \sqrt{\dfrac{2}{165} }\\\\T=0.69\ s

The frequency of vibration is reciprocal of its time period. So,

f=\dfrac{1}{T}\\\\f=\dfrac{1}{0.69}\\\\f=1.44\ Hz

So, the period of the mass-spring system is 0.69 s and frequency is 1.44 Hz.

3 0
4 years ago
Help please i need it asap
mojhsa [17]

Answer:

B

Explanation:

B, because if u subtract the forces from each other the forward one outweights the other ones

6 0
3 years ago
Read 2 more answers
A 0.50 kg object is at rest. A 2.88 N force to the right acts on the object during a time interval of 1.48 s. a) What is the vel
Murljashka [212]

Answer:

8.5m/s

Explanation:

We are given that

Mass of object=m=0.50 kg

Initial velocity, u=0

Force=F=2.88 N

Time=1.48 s

a.We know that

F=ma

Using the formula

2.88=0.50a

a=\frac{2.88}{0.50}=5.76m/s^2

a=\frac{v-u}{t}

Using the formula

5.76=\frac{v-0}{1.48}

v=5.76\times 1.48=8.5m/s

Hence, the velocity of the object at the end of this time interval=8.5m/s

8 0
3 years ago
A NASA centrifuge spins astronauts around in a compartment attached to a long arm. A diagram of the centrifuge is shown below.
Brut [27]
14.5 g I'm guessing lol I just got this from what you wrote just joined the website why do I have to write 20 charcters tho?

6 0
4 years ago
Read 2 more answers
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