To solve this problem we will apply the concept of wavelength, which warns that this is equivalent to the relationship between the speed of the air (in this case in through the air) and the frequency of that wave. The air is in standard conditions so we have the relation,
Frequency 
Speed of sound in air 
The definition of wavelength is,
Here,
v = Velocity
f = Frequency
Replacing,
Therefore the wavelength of that tone in air at standard conditions is 0.589m
<span>A. Rocket A will travel farther horizontally than rocket B.
This is because from the x axis, 40 m/s at 90 degrees travels directly vertical. 40 m/s at 70 degrees is slightly horizontal, so it will travel further horizontally.</span>
Answer:
The motorbike is traveling at 40 m/s
Explanation:
100m over 2.5 seconds or 100/2.5 is 40 m/s
Fortunately, 'force' is a vector. So if you know the strength and direction
of each force, you can easily addum up and find the 'resultant' (net) force.
When we talk in vectors, one newton forward is the negative of
one newton backward. Hold that thought, while I slog through
the complete solution of the problem.
(100 N forward) plus (50 N backward)
= (100 N forward) minus (50 N forward)
= 50 N forward .
That's it.
Is there any part of the solution that's not clear ?
Answer:
a) the frequency of the wave is 0.2 Hz
b) the speed of the wave 4 m/s
Explanation:
Given that;
time period = to complete one cycle t = 5 sec
frequency f = 1/t
frequency f = 1 / 5sec
f = 0.2 Hz
Therefore the frequency of the wave is 0.2 Hz
b)
speed of wave V = λf
given that our wavelength is 20.0 m
we substitute
speed of wave V = 20.0 × 0.2
speed of wave V = 4 m/s
Therefore, the speed of the wave 4 m/s
