Answer:
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Explanation:
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The two factors that affect the electric force are the charges and the separation between the objects
Explanation:
The magnitude of the electrostatic force between two objects is given by Coulomb's law:
where:
is the Coulomb's constant
are the charges of the two objects
r is the separation between the two objects
Looking at the equation, we see that the electric force between objects depends on two factors:
- The charges of the objects: the force is directly proportional to the product of the two charges, therefore the greater the charges, the stronger the force
- The distance between the two objects: the force is inversely proportional to the square of the distance, therefore the smaller the distance between the objects, the stronger the force
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To develop this problem it is necessary to apply the concepts related to Gravitational Potential Energy.
Gravitational potential energy can be defined as

As M=m, then

Where,
m = Mass
G =Gravitational Universal Constant
R = Distance /Radius
PART A) As half its initial value is u'=2u, then



Therefore replacing we have that,

Re-arrange to find v,



Therefore the velocity when the separation has decreased to one-half its initial value is 816m/s
PART B) With a final separation distance of 2r, we have that

Therefore




Therefore the velocity when they are about to collide is 
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Just do what u would do if u were at a stop sign