Answer:
2.5A , 22500 JOULE
Explanation:
Resistance (R)= 6 ohm
Voltage (V) = 15 volt
a)
Current (I) = ?
From ohm's law,
V=IR
15 = 6*I
I = 2.5 A
b)
time(t) = 10min = 600 second
heat energy (Q) = ?
from Joule's law of heating,
Q = I²*R*t
Q = 2.5² *6*600
Q = 22500 Joule
hence, heat energy produced is 22500 joule.
Answer:
1/4
Explanation:
If the distance between two charges is doubled, the attraction of repulsion between the two becomes weaker, and decreases to 1/4 of the original value.
Answer:
0.7757 rev/s
Explanation:
d = Diameter of the tornado = 53 m
r = Radius of the tornado = 53/2 = 26.5 m
v = Velocity of wind = 465 km/h
Converting velocity to m/s
Angular velocity
∴ Angular velocity is 0.7757 rev/s
Answer:
72.75 kg m^2
Explanation:
initial angular velocity, ω = 35 rpm
final angular velocity, ω' = 19 rpm
mass of child, m = 15.5 kg
distance from the centre, d = 1.55 m
Let the moment of inertia of the merry go round is I.
Use the concept of conservation of angular momentum
I ω = I' ω'
where I' be the moment of inertia of merry go round and child
I x 35 = ( I + md^2) ω'
I x 35 = ( I + 25.5 x 1.55 x 1.55) x 19
35 I = 19 I + 1164
16 I = 1164
I = 72.75 kg m^2
Thus, the moment of inertia of the merry go round is 72.75 kg m^2.
Answer:
The answer is Dependent Variable
