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2 years ago

The rod connected halfway along the 0.660 m radius of a wheel exerts a 2.27 × 10^5 N force. How large is the maximum torque?

Physics

1 answer:

Klio2033 [76]2 years ago

3 0

Answer:

1.498×10⁵ Nm

Explanation:

From the question above,

Torque (T) = Force (F) × radius (r)

T = F×r............................. Equation 1

Where T = Torque, F = force, r = radius .

Given: F = 2.27×10⁵ N, r = 0.660 m

Substitute these values into equation 1

T = 2.27×10⁵×0.660

T = 1.498×10⁵ Nm

Hence the torque of the wheel is 1.498×10⁵ Nm

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A commonly used unit of electrical energy.

ladessa [460]

The two most common units of electric energy is Watts or hertz.

8 0

3 years ago

At one point in a pipeline, the water's speed is 3.57 m/s and the gauge pressure is 68.7 kPa. Find the gauge pressure at a secon

ArbitrLikvidat [17]

Answer:

The pressure at point 2 is $P_2 = 254.01 kPa$

Explanation:

From the question we are told that

The speed at point 1 is $v_1 = 3.57 \ m/s$

The gauge pressure at point 1 is $P_1 = 68.7kPa = 68.7*10^{3}\ Pa$

The density of water is $\rho = 1000 \ kg/m^3$

Let the height at point 1 be $h_1$ then the height at point two will be

$h_2 = h_1 - 18.5$

Let the diameter at point 1 be $d_1$ then the diameter at point two will be

$d_2 = 2 * d_1$

Now the continuity equation is mathematically represented as

$A_1 v_1 = A_2 v_2$

Here $A_1 , A_2$ are the area at point 1 and 2

Now given that the are is directly proportional to the square of the diameter [i.e $A= \frac{\pi d^2}{4}$ ]

which can represent as

$A \ \ \alpha \ \ d^2$

=> $A = c d^2$

where c is a constant

so $\frac{A_1}{d_1^2} = \frac{A_2}{d_2^2}$

=> $\frac{A_1}{d_1^2} = \frac{A_2}{4d_1^2}$

=> $A_2 = 4 A_1$

Now from the continuity equation

$A_1 v_1 = 4 A_1 v_2$

=> $v_2 = \frac{v_1}{4}$

=> $v_2 = \frac{3.57}{4}$

$v_2 = 0.893 \ m/s$

Generally the Bernoulli equation is mathematically represented as

$P_1 + \frac{1}{2} \rho v_1^2 + \rho * g * h_1 = P_2 + \frac{1}{2} \rho v_2^2 + \rho * g * h_2$

$P_2 = \rho * g (h_1 -h_2 )+P_1 + \frac{1}{2} * \rho (v_1^2 -v_2 ^2 )$

=> $P_2 = \rho * g (h_1 -(h_1 -18.3) + P_1 + \frac{1}{2} * \rho (v_1^2 -v_2 ^2 )$

substituting values

$P_2 = 1000 * 9.8 (18.3) )+ 68.7*10^{3} + \frac{1}{2} * 1000 ((3.57)^2 -0.893 ^2 )$

$P_2 = 254.01 kPa$

8 0

2 years ago

Ike is at the beach watching the waves in the ocean. Ike notices that some of the waves are short. Other waves are very tall and

aniked [119]

Ike is at the beach watching the waves in the ocean. Ike notices that some of the waves are short. Other waves are very tall and come up high above the water. Two waves that are different heights because They have different amplitudes.

Answer: Option (D) is correct

Explanation:

The different heights of the waves are due to their different amplitudes. The Amplitude of a particular wave depends upon the amount of energy being carried by waves. It the waves carry more energy than their amplitude will be higher.

But if energy carried by a wave is less than the wave will have a low amplitude. The Amplitude shows the distance covered from the rest position to peak position.

3 0

2 years ago

HI PLEASE HELP, I ONLY HAVE 10 MINUTES

Whitepunk [10]

Answer:

um ok

?????

i dont like you get rejected

jk u gud

Explanation:

5 0

2 years ago

If an object has a mass of 25 grams and a volume of 5 mL, then what is the density of the object?

vazorg [7]

Answer:

Explanation:

density = mass/volume

density = 25g /5 mL

density = 5

6 0

2 years ago