It’s because flourecent lights operate at higher temperatures than incadecent lights.
Answer:
All of the above.
Explanation:
All Machines make work easier.
They can move objects.
They have multiple parts.
And the use energy.
There's no way to tell. Without seeing a diagram of the circuit,
I'll need to know much more about it than you've told me.
I don't know anything about the components or power supply
that are in the circuit, and I don't know where point ' f ' is in it.
Right now, even with the copious volume of all the available
information, no answer to your question is possible.
Characteristics, such as field name and data type are properties that define a field.
<h3>What are the properties of a given discipline or research field?</h3>
The properties of a given discipline or research field are those that characterize the use of a particular type of information within the range of the attained field.
For example, genomics is a field characterized to make use of sequencing data, which refers to the linear order of nucleotides in the DNA sequence to provide useful information about the gene content and the presence of regulatory non-coding sequences.
Therefore, with this data, we can see that the properties of a given discipline or research field are mainly associated with the type of information that such discipline uses to make predictions in a given research and they are also related to the outcomes we can expect from such data.
Learn more about the properties of a scientific research field here:
brainly.com/question/17242319
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Answer:
The extra force exerted against the bottom is 5880 N.
Explanation:
Given that,
Diameter of the bottle= 2.00 cm
Diameter of the jug = 14.0 cm
Force = 120 N
We need to calculate the extra force exerted against the bottom
Using formula of force
![F_{2}=P\times A_{2}](https://tex.z-dn.net/?f=F_%7B2%7D%3DP%5Ctimes%20A_%7B2%7D)
![F_{2}=\dfrac{F_{1}}{A_{1}}\times A_{2}](https://tex.z-dn.net/?f=F_%7B2%7D%3D%5Cdfrac%7BF_%7B1%7D%7D%7BA_%7B1%7D%7D%5Ctimes%20A_%7B2%7D)
![F_{2}=\dfrac{F_{1}}{\pi r^2}\times\pi r^2](https://tex.z-dn.net/?f=F_%7B2%7D%3D%5Cdfrac%7BF_%7B1%7D%7D%7B%5Cpi%20r%5E2%7D%5Ctimes%5Cpi%20r%5E2)
![F_{2}=\dfrac{F_{1}}{\pi\times\dfrac{d_{1}^2}{4}}\times\pi\times\dfrac{d_{2}^2}{4}](https://tex.z-dn.net/?f=F_%7B2%7D%3D%5Cdfrac%7BF_%7B1%7D%7D%7B%5Cpi%5Ctimes%5Cdfrac%7Bd_%7B1%7D%5E2%7D%7B4%7D%7D%5Ctimes%5Cpi%5Ctimes%5Cdfrac%7Bd_%7B2%7D%5E2%7D%7B4%7D)
![F_{2}=(\dfrac{d_{2}}{d_{1}})^2\times F_{1}](https://tex.z-dn.net/?f=F_%7B2%7D%3D%28%5Cdfrac%7Bd_%7B2%7D%7D%7Bd_%7B1%7D%7D%29%5E2%5Ctimes%20F_%7B1%7D)
Put the value into the formula
![F_{2}=(\dfrac{14.0}{2.00})^2\times120](https://tex.z-dn.net/?f=F_%7B2%7D%3D%28%5Cdfrac%7B14.0%7D%7B2.00%7D%29%5E2%5Ctimes120)
![F_{2}=5880\ N](https://tex.z-dn.net/?f=F_%7B2%7D%3D5880%5C%20N)
Hence, The extra force exerted against the bottom is 5880 N.