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adoni [48]
3 years ago
9

The lamp cord is 85cm long and comprises cupper wire. Calculate the wire‘s resistance?

Physics
1 answer:
DaniilM [7]3 years ago
3 0

Answer:

R = 0.0015Ω

Explanation:

The formula for calculating the resistivity of a material is expressed as;

ρ = RA/l

R is the resistance

ρ is the resistivity

A is the area of the wire

l is the length of the wire

Given

l = 85cm = 0.85m

A = πr²

A = 3.14*0.0018²

A = 0.0000101736m²

ρ = 1.75 × 10-8Ωm.

Substitute into the formula

1.75 × 10-8 = 0.0000101736R/0.85

1.4875× 10-8 = 0.0000101736R

R = 1.4875× 10-8/0.0000101736

R = 0.0015Ω

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I was watching quantum leap and I was wondering if we can actually travel through different people's body without knowing it's a
alukav5142 [94]

Answer:

No you could not do that because if you tried even if you where to go super fast they would feel a breif second of pain before being completely riped from there body

7 0
3 years ago
A phoneme is the largest unit of sound in a word.
lukranit [14]

This question is incomplete; here is the complete question:

A phoneme is the largest unit of sound in a word. Please select the best answer from the choices provided

A. T

B. F

The correct answer to this question is F (False)

Explanation:

The word "phoneme" is used to refer to the minimal unit of sound in words, and therefore in language. For example, the first phoneme in the word "man" is "m". These units of sound are essential in language because they make each word unique in meaning and sound. For example, "fan" and "man" are different due to the phonemes "m" and "f". According to this, the phone is not the largest unit of sound but the smallest unit.

7 0
3 years ago
Read 2 more answers
Early black-and-white television sets used an electron beam to draw a picture on the screen. The electrons in the beam were acce
lutik1710 [3]

Answer:

speed of electrons = 3.25 × 10^{7} m/s

acceleration in term g is 3.9 × 10^{17} g.

radius of circular orbit is 2.76 × 10^{-4} m

Explanation:

given data

voltage = 3 kV

magnetic field = 0.66 T

solution

law of conservation of energy

PE = KE

qV = 0.5 × m × v²

v = \sqrt{\frac{2qV}{m}}

v = \sqrt{\frac{2\times 1.6 \times 10^{-19}\times 3}{9.1\times 10^{-31}}

v = 3.25 × 10^{7} m/s

and

magnetic force on particle movie in magnetic field

F = Bqv

ma = Bqv

a = \frac{Bqv}{m}  

a =  \frac{0.67\times 1.6\times 10^{-19}\times 3.25\times 10^7}{9.1\times 10^{-31}}

a = 3.82 × 10^{18} m/s²

and acceleration in term g

a = \frac{3.82\times 10^{18}}{9.81}  

a = 3.9 × 10^{17} g

acceleration in term g is 3.9 × 10^{17} g.

and

electron moving in circular orbit has centripetal force

F = \frac{mv^2}{r}  

Bqv = \frac{mv^2}{r}  

r = \frac{mv}{Bq}  

r = \frac{9.1\times 10^{-31}\times 3.25\times 10^7}{0.67\times 1.6\times 10^{-19}}  

r = 2.76 × 10^{-4} m

radius of circular orbit is 2.76 × 10^{-4} m

8 0
3 years ago
Calculate the speed for a car that went a distance of 125 meters in 2 seconds time.
stiv31 [10]

Answer:

<h2>62.5 m/s</h2>

Explanation:

The speed of the car can be found by using the formula

s =  \frac{d}{t} \\

d is the distance

t is the time

From the question we have

s =  \frac{125}{2}  = 62.5 \\

We have the final answer as

<h3>62.5 m/s</h3>

Hope this helps you

5 0
2 years ago
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Fed [463]

Answer:

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6 0
3 years ago
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