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3 years ago

What type of reaction results in the formation of a salt?

1 answer:

5 0

Salt, in chemistry, substance produced by the reaction of an acid with a base. A salt consists of the positive ion (cation) of a base and the negative ion (anion) of an acid. The reaction between an acid and a base is called a neutralization reaction. Hope this helps!!!

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NikAS [45]

D, Metamorphism
-Metamorphic rocks are any rocks that change into another rock when subjected to high heat and pressure.

7 0

3 years ago

Assume that, as the battery wears out, the voltage decreases at 0.03 volts per second and, as the resistor heats up, the resista

liraira [26]

Answer:

$\frac{dI}{dt} =-3*10^-^4amps/sec$

Explanation:

From the question we are told that

Voltage decreases at $\frac{dv}{dt} =-0.03volts/sec$

Resistance increase at $\frac{dR}{dt}=0.02ohms /sec$

Resistance at $R=100ohms$

Current at $I=0.02amps$

Generally the equation for ohms law is mathematically represented as

$V=IR$

Therefore

$\frac{dV}{dt} =R\frac{dI}{dt} +I\frac{dR}{dt}$

Generally making $\frac{dI}{dt}$ subject of the formula in the above equation mathematically gives

$\frac{dV}{dt} =R\frac{dI}{dt} +I\frac{dR}{dt}$

$R\frac{dI}{dt} = \frac{dV}{dt} -I\frac{dR}{dt}$

$\frac{dI}{dt} =\frac{1}{R} (\frac{dV}{dt} -I\frac{dR}{dt})$

Therefore

$\frac{dI}{dt} =\frac{1}{100}((-0.03) -(0.02)*(0.02))$

Generally it is given that the change in current is

$\frac{dI}{dt} =-3*10^-^4amps/sec$

8 0

3 years ago

a proton of mass 1 u travelling with a speed of 3.6 x 10 ^4 m/s has an elastic head on collision with a helium nucleus initially

CaHeK987 [17]

Answer:

Velocity of the helium nuleus = 1.44x10⁴m/s

Velocity of the proton = 2.16x10⁴m/s

Explanation:

From the conservation of linear momentum of the proton collision with the He nucleus:

$P_{1i} + P_{2i} = P_{1f} + P_{2f]$ (1)

where $P_{1i}$ : is the proton linear momentum initial, $P_{2i}$ : is the helium nucleus linear momentum initial, $P_{1f}$ : is the proton linear momentum final, $P_{2f}$ : is the helium nucleus linear momentum final

From (1):

$m_{1}v_{1i} + 0 = m_{1}v_{1f} + m_{2}v_{2f}$ (2)

where m₁ and m₂: are the proton and helium mass, respectively, $v_{1i}$ and $v_{2i}$ : are the proton and helium nucleus velocities, respectively, before the collision, and $v_{1f}$ and $v_{2f}$ : are the proton and helium nucleus velocities, respectively, after the collision

By conservation of energy, we have:

$K_{1i} + K_{2i} = K_{1f} + K_{2f}$ (3)

where $K_{1i}$ and $K_{2i}$ : are the kinetic energy for the proton and helium, respectively, before the colission, and $K_{1f}$ and $K_{2f}$ : are the kinetic energy for the proton and helium, respectively, after the colission

From (3):

$\frac{1}{2}m_{1}v_{1i}^{2} + 0 = \frac{1}{2}m_{1}v_{1f}^{2} + \frac{1}{2}m_{2}v_{2f}^{2}$ (4)

Now we have two equations: (2) ad (4), and two incognits: $v_{1f}$ and $v_{2f}$ .

Solving equation (2) for $v_{1f}$ , we have:

$v_{1f} = v_{1i} -\frac{m_{2}}{m_{1}} v_{2f}$ (5)

From getting (5) into (4) we can obtain the $v_{2f}$ :

$v_{2f}^{2} \cdot (\frac{m_{2}^{2}}{m_{1}} + m_{2}) - 2v_{2f}v_{1i}m_{2} = 0$

$v_{2f}^{2} \cdot (\frac{(4u)^{2}}{1u} + 4u) - v_{2f}\cdot 2 \cdot 3.6 \cdot 10^{4} \cdot 4u = 0$

From solving the quadratic equation, we can calculate the velocity of the helium nucleus after the collision:

$v_{2f} = 1.44 \cdot 10^{4} \frac{m}{s}$ (6)

Now, by introducing (6) into (5) we get the proton velocity after the collision:

$v_{1f} = 3.6 \cdot 10^{4} -\frac{4u}{1u} \cdot 1.44 \cdot 10^{4}$

$v_{1f} = -2.16 \cdot 10^{4} \frac{m}{s}$

The negative sign means that the proton is moving in the opposite direction after the collision.

I hope it helps you!

7 0

4 years ago

How do you spell hard water in three letters.

Kay [80]

Ice, which is the solid state of water, the liquid

5 0

4 years ago

Read 2 more answers

A man standing on a bus remains still when the bus is at rest. When the bus moves forward and then slows down the man continues

vovikov84 [41]

When the bus starts moving forward, the man remains at rest,
causing him to lean back.

When the bus slows down, the man continues to move forward,
and appears to lean forward.

Both events are examples of the effect of inertia.

6 0

4 years ago