Answer:
Explanation:
The magnitude of the electric force on this charged particle A depends upon the following
5. the distance between the point charge Q and the charged particle A
8. the amount of the charge on the point charge Q
9. the magnitude of charge on the charged particle A
Answer:
Explanation:
velocity of light in a medium of refractive index V = V₀ / μ
V₀ is velocity of light in air and μ is refractive index of light.
time to travel in tube with air = length of tube / velocity of light
8.72 ns = L / V₀ L is length of tube .
time to travel in tube with jelly = length of tube / velocity of light
8.72+ 1.82 = L / V L is length of tube .
10.54 ns = L / V
dividing the equations
10.54 / 8.72 = V₀ / V
10.54 / 8.72 = μ
1.21 = μ
refractive index of jelly = 1.21 .
0.2 is the value of coefficient of friction (k)
F=kN
F=horizontal force
n=Normal Force
k=coefficient of friction
k=F/N
k=200/1000
k=0.2
The ratio of the normal force pushing two surfaces together to the frictional force preventing motion between them is known as the friction coefficient. Usually, the Greek letter mu is used to indicate it .N is the normal force, and F is the frictional force, hence F = N/N.
Due to the fact that both F and N are measured in units of force, the coefficient of friction has no dimensions (such as newtons or pounds). The coefficient of friction can have a variety of values for both static and dynamic friction. Static friction occurs when an object encounters friction that resists any applied force, keeping the object at rest until the static frictional force is released. In kinetic friction, the frictional force resists the motion of the object.
To know more about coefficient of friction visit brainly.com/question/136431
#SPJ1
Answer:
distance r from the uranium atom is 18.27 nm
Explanation:
given data
uranium and iron atom distance R = 44.10 nm
uranium atom = singly ionized
iron atom = doubly ionized
to find out
distance r from the uranium atom
solution
we consider here that uranium electron at distance = r
and electron between uranium and iron so here
so we can say electron and iron distance = ( 44.10 - r ) nm
and we know single ionized uranium charge q2= 1.602 ×
C
and charge on iron will be q3 = 2 × 1.602 ×
C
so charge on electron is q1 = - 1.602 ×
C
and we know F =
so now by equilibrium
Fu = Fi
=
put here k =
and find r
=
![\frac{1}{r^{2} } = \frac{2}{(44.10 -r)^2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Br%5E%7B2%7D%20%7D%20%3D%20%5Cfrac%7B2%7D%7B%2844.10%20-r%29%5E2%7D)
r = 18.27 nm
distance r from the uranium atom is 18.27 nm
The velocity of the brick is 39.2 m/s downward
Explanation:
The motion of the brick is a free fall motion, since the object is affected only by the force of gravity. Therefore, it has a uniformly accelerated motion towards the ground, with constant acceleration of
.
So, we can find its velocity using the suvat equation:
![v=u+at](https://tex.z-dn.net/?f=v%3Du%2Bat)
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time
For the brick in this problem (taking downward as positive direction)
u = 0 (it is dropped from rest)
![a=g=9.8 m/s^2](https://tex.z-dn.net/?f=a%3Dg%3D9.8%20m%2Fs%5E2)
Therefore, its velocity after t = 4.0 s is:
![v=0+(9.8)(4.0)=39.2 m/s](https://tex.z-dn.net/?f=v%3D0%2B%289.8%29%284.0%29%3D39.2%20m%2Fs)
Downward, because the sign is positive.
Learn more about free fall motion:
brainly.com/question/1748290
brainly.com/question/11042118
brainly.com/question/2455974
brainly.com/question/2607086
#LearnwithBrainly