All categories

3 years ago

How many molecules are present in 2 H₂ SO4

Chemistry

1 answer:

Delvig [45]3 years ago

3 0

Answer:

1 mol of H2SO4 contains 6.022 x 10^23 molecules. : 0.5 mol of H2SO4 contains 0.5 x 6.022 x 10^23 molecules. = 3.011 x 10^23 molecules . that is 49 g of H2SO4 contains 3.011 x 10^23 molecules of H2SO

Explanation:

You might be interested in

a sample of gas initially occupies 5.50 liter at a pressure of 0.750 atm at 13.0 C. what will the temperture change to 22.5 C an

sergey [27]

Answer:

The pressure will be 2.84 atm

Explanation:

The gas laws are a set of chemical and physical laws that allow us to determine the behavior of gases in a closed system. The parameters evaluated in these laws are pressure, volume, temperature and moles.

Boyle's law indicates that the volume is inversely proportional to the pressure: if the pressure increases, the volume decreases and if the pressure decreases, the volume increases. Boyle's law is expressed mathematically as:

P * V = k

On the other hand, Charles's law indicates that with increasing temperature, the volume of the gas increases and with decreasing temperature, the volume of the gas decreases. That is, they are directly proportional. This is expressed mathematically as:

$\frac{V}{T} =k$

Finally, the Gay-Lussac law says that at constant volume, the pressure of the gas is directly proportional to its temperature. Mathematically, it is expressed as:

$\frac{P}{T} =k$

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

$\frac{P*V}{T}=k$

When you want to study two different states, an initial and a final one of a gas, you can use the following expression:

$\frac{P1*V1}{T1}=\frac{P2*V2}{T2}$

In this case:

P1= 0.750 atm
V1= 5.50 L
T1= 13 C= 286 K (being 0 C=273 K)
P2=?
V2= 1.50 L
T2= 22.5 C=295.5 K

Replacing:

$\frac{0.750 atm*5.50 L}{286 K}= \frac{P2*1.50 L}{295.5 K}$

Solving:

$P2=\frac{295.5K}{1.50L} *\frac{0.750 atm*5.50 L}{286 K}$

P2= 2.84 atm

<u><em>The pressure will be 2.84 atm</em></u>

8 0

4 years ago

Q1. Briefly explain why the Zeff experienced by a valence electron in Cl is larger than in Mg. Q2. Briefly explain why the Zeff

Inessa05 [86]

Answer:

See explanation

Explanation:

Q1:

Chlorine has 17 protons while magnesium has only 12 protons. Recall that the Zeff depends on the size of the nuclear charge. The greater the size of the nuclear charge, the larger the Zeff experienced by a valence electron.

Q2:

The larger the Zeff, the smaller the atomic radius. Since the valence electrons of Cl experience a greater Zeff than those of Mg due to greater size of the nuclear charge, the atomic radius of chlorine will be smaller than that of Mg.

Q3:

The radius of an atom increases as the value of the principal quantum number (n) increases down the group due to addition of more shells. The greater the number of shells added, the greater the principal quantum number (n) and the greater the atomic radius, hence the answer.

5 0

3 years ago

34.1 mg NaCl in 117.3 mL of solution

Solnce55 [7]

The molarity of the solution will be 4.97 M.

<h3>What is molarity?</h3>

It is the number of moles of solutes per 1 liter of solvent or solution.

Mole of 34.1 g NaCl = 34.1/58.44 = 0.5835 mol

117.3 mL = 117.3/1000 = 0.1173 L

Molarity of the solution = 0.5835/0.1173 = 4.97 M

More on molarity can be found here: brainly.com/question/2817451

#SPJ1