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Dima020 [189]
3 years ago
8

The decomposition of hydrogen peroxide follows first order kinetics and has a rate constant of 2.54 x 10-4 s-1 at a certain temp

erature. If the concentration of hydrogen peroxide is 0.321 M after 855 s , what was the initial concentration of hydrogen peroxide at this temperature
Chemistry
1 answer:
Eva8 [605]3 years ago
3 0

Answer:

[A]_0=0.400M

Explanation:

Hello.

In this case, since the first-order reaction is said to be linearly related to the rate of reaction:

r=-k[A]

Whereas [A] is the concentration of hydrogen peroxide, when writing it as a differential equation we have:

\frac{d[A]}{dt} =-k[A]

Which integrated is:

ln(\frac{[A]}{[A]_0} )=-kt

And we can calculate the initial concentration of the hydrogen peroxide as follows:

[A]_0=\frac{[A]}{exp(-kt)}

Thus, for the given data, we obtain:

[A]_0=\frac{0.321M}{exp(-2.54x10^{-4}s^{-1}*855s)}

[A]_0=0.400M

Best regards!

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Explanation:

Roman numeral is used to indicate the oxidation number of an element in a compound.

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This can be seen from the following illustration:

copper(I) oxide => Cu₂O

Oxidation number of O = –2

Oxidation number of Cu₂O = 0

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Thus, we can see that the oxidation number of Cu in Cu₂O is 1. Hence the name of Cu₂O is copper(I) oxide indicating that the oxidation number of of copper (Cu) in the compound is 1.

For copper(II) oxide, we shall determine the oxidation number of Cu. This can be obtained as follow:

copper(II) oxide, CuO => CuO

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Thus, the oxidation number of Cu in CuO is 2. Hence the name of CuO is copper(II) oxide indicating that the oxidation number of of copper (Cu) in the compound is 2.

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