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sattari [20]
3 years ago
15

Use the galvanometers to determine the amount and direction of the induced current. Which galvanometer is

Physics
1 answer:
docker41 [41]3 years ago
4 0

Answer:

Option B

Explanation:

Looking at the 3 galvanometer readings given above, for galvanometer A, the reading is -2 mA.

For galvanometer B, the reading is 4 mA.

While for galvanometer C, the reading is -5 MA

Thus, option B is correct.

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1. Two forces F~ 1 and F~ 2 are acting on a block of mass m=1.5 kg. The magnitude of force F~ 1 is 12N and it makes an angle of
VLD [36.1K]

Answer:

Normal force=7.48 N

Explanation:

N+F~1 sinθ-mg=0

=>N=1.5*9.8-12 sin37◦

=>N=14.7-7.22=7.48 N

6 0
2 years ago
A ______ is a closed loop containing a source of electrical energy and a load.
gavmur [86]

Answer:

d. circuit

Explanation:

the parts of the circuit consists of a load or resistance

7 0
3 years ago
A ball is projected upward at time t = 0.0 s, from a point on a roof 70 m above the ground. The ball rises, then falls and strik
pentagon [3]

Answer:

The velocity of a ball will be "-70.13 m/s".

Explanation:

The given values are:

u = 70 m

t = 0.0 s

g = a = -9.8 m/s²

s = -1 m

v = ?

As we know,

The equation of motion will be:

⇒  v^2-u^2=2as

On substituting the estimated values, we get

⇒  v^2-(70)^2=2\times (-9.8)\times (-1)

⇒  v^2-4900=19.6

⇒  v^2=19.6+4900

⇒  v^2=4919.6

⇒  v=\sqrt{4919.6}

⇒  v=70.13 \ m/s

In downward direction, it will be:

⇒  v=-70.13 \ m/s

8 0
2 years ago
a object with a mass of 70 kilograms is supported at a height 8 meters above the ground.what's the potential energy of the objec
Agata [3.3K]
Potential Energy = mgh,

where m = mass in kg,  g ≈ 10 m/s², h = height above ground = 8 m

PE = mgh
  
      = 70*10*8 = 5600 J

7 0
3 years ago
What is the kinetic energy of a 0.15 kg baseball that is moving with a velocity of 50 m/s?
goblinko [34]
Using the equation:

ke \:  =  \frac{1}{2} m{v}^{2}
ke  =   \frac{1}{2} (0.15) {(50)}^{2}
ke  = 188  \: (3sf)


Ans: 188 J
7 0
2 years ago
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