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Ymorist [56]
3 years ago
12

What is the most abundant gas in the atmosphere?

Physics
1 answer:
Snowcat [4.5K]3 years ago
8 0

Answer: Nitrogen

Explanation: Nitrogen makes up 78% of the atmosphere, Oxygen makes up 21%, and Argon 0.9%.

Water vaper makes up between 1-4%, depending on the region.

Carbon Dioxide makes up only about 0.04%.

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The siren on an ambulance is emitting a sound whose frequency is2550 Hz. The speed of sound is 343 m/s.(a) If the ambulance is s
Sati [7]

Answer:

0.13451 m

0.124196 m

0.119997901132 m

Explanation:

v_o = Velocity of the observer

v_s = Velocity of sound source

v = Velocity of sound in air = 343 m/s

Wavelength is given by

\lambda=\dfrac{v}{f}\\\Rightarrow \lambda=\dfrac{343}{2550}\\\Rightarrow \lambda=0.13451\ m

The wavelength is 0.13451 m

From Doppler effect we have the formula

f=f'\dfrac{v}{v-v_s}\\\Rightarrow f=2550\dfrac{343}{343-26.3}\\\Rightarrow f=2761.7619198\ Hz

\lambda=\dfrac{343}{2761.7619198}\\\Rightarrow \lambda=0.124196\ m

The wavelength is 0.124196 m

f=f'\dfrac{v+v_o}{v-v_s}\\\Rightarrow f=2550\dfrac{343+12}{343-26.3}\\\Rightarrow f=2858.38332807\ Hz

\lambda=\dfrac{343}{2858.38332807}\\\Rightarrow \lambda=0.119997901132\ m

The wavelength is 0.119997901132 m

8 0
4 years ago
The most distal part of a nail is called the ____________ . The most proximal part of the nail that is embedded in the skin is t
ankoles [38]

Answer:

1.Free edge

2.Nail Root

3.Nail matrix

4.lunula

Note: The numbering coincides respectively with the dashes in the questions.

Explanation:

Free edge is the distal white nail ending.

Nail Root is the proximal part of the nail embedded in the skin.

Nail matrix is the actively growing part of the nail were the nail root thickens

Lunula the whitish semilunar area of the proximal end of the nail body it appears whitish because stratum basala obscures. the underlying blood vessels.

7 0
3 years ago
(b) The figure below shows a model train, travelling at speed , approaching a
Andrew [12]

Answer:

0.62 m/s

Explanation:

Given that a model train, travelling at speed , approaching a buffer model train buffer spring

The train, of mass 2.5 kg, is stopped by compressing a spring in the buffer.

After the train has stopped, the energy stored in the spring is 0.48 J.

Calculate the initial speed v of the train

Solution

The total energy stored in the spring will be equal to the kinetic energy of the train.

That is,

1/2fe = 1/2mv^2

Substitutes the spring energy, and mass into the formula

0.48 = 1/2 × 2.5 × V^2

2.5V^2 = 0.96

V^2 = 0.96 / 2.5

V^2 = 0.384

V = sqrt ( 0.384 )

V = 0.62 m/s

Therefore, the initial velocity of the train is 0.62 metres per second.

3 0
3 years ago
As global population ______
Sedbober [7]

Answer:

As global population a.) <u>increases</u> food production must a.) <u>increase</u>.

Example:

More people means more food must be produced.

6 0
3 years ago
Suppose it to hour and 30 minutes for an airplane to travel a distance of 350 mi from San Francisco to Los Angeles.
DanielleElmas [232]

Answer:

ppp

Explanation:

3 0
3 years ago
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