<u>Answer:</u> The mass of solid NaOH required is 80 g
<u>Explanation:</u>
Equivalent weight is calculated by dividing the molecular weight by n factor. The equation used is:

where,
n = acidity for bases = 1 (For NaOH)
Molar mass of NaOH = 40 g/mol
Putting values in above equation, we get:

Normality is defined as the umber of gram equivalents dissolved per liter of the solution.
Mathematically,

Or,
......(1)
We are given:
Given mass of NaOH = ?
Equivalent mass of NaOH = 40 g/eq
Volume of solution = 400 mL
Normality of solution = 5 eq/L
Putting values in equation 1, we get:

Hence, the mass of solid NaOH required is 80 g
Answer: 4 : 3
Explanation:Please see attachment for explanation
Answer:
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Answer : The mass percentage of isopropyl alcohol in the solution is, 59.4 %
Explanation :
To calculate the mass percentage of isopropyl alcohol in the solution, we use the equation:

Mass of isopropyl alcohol = 6.68 g
Mass of isopropyl alcohol solution = 3.97 g
Putting values in above equation, we get:

Thus, the mass percentage of isopropyl alcohol in the solution is, 59.4 %