The answer is: 8.14·10⁶³ moles of lithium are present.
N(Li₂SO₄) = 2.45·10⁸⁷; number of formula units of lithium sulfate.
n(Li₂SO₄) = N(Li₂SO₄) ÷ Na.
n(Li₂SO₄) = 2.45·10⁸⁷ ÷ 6.022·10²³ 1/mol.
n(Li₂SO₄) = 4.07·10⁶³ mol; amount of lithium sulfate
In one molecule of lithium sulfate, there are two atoms of lithium.
n(Li₂SO₄) : n(Li) = 1 : 2.
n(Li) = 2 · 4.07·10⁶³ mol.
n(Li) = 8.14·10⁶³ mol; amount of lithium atoms.
Mass = protons + neutrons
7+8 = 15 g
Answer:
Hence , in a century<u> 0.342 liters</u> of the liquid will drip.
Explanation:
The rate of the flow of the liquid droplet is given by:


<u>Unit conversion:</u>
We need to change mL/hr into Liter/century
1 L = 1000 mL (given)
1 mL = 0.001 L......(1)
1 century = 100 year
1 year = 365 days
So, 1 century = 100 x 365 days = 36500 days
1 day = 24 hrs
So , 36500 days = 36500 x 24 hr = 876000 hr
Hence ,
1 century = 36500 days = 876000 hr
we are not asked to calculate the answer in days
1 century = 876000 hr
1 hr = 1/ 876000 century
.....(2)
From (1) and (2) put the value in the given formula:
This is for 1 mL/hr to 1 L/century
Now for 300 mL/hr . the rate will be more , multiply the answer by 300
Rate = 0.342 Liters / century
Hence , in a century 0.342 liters of the liquid will drip.
Answer:
(a) 
(b) 
(c) 
(d) 
(e) 
Explanation:
To calculate de pH of an acid solution the formula is:
![pH = -Log ([H^{+}]) = 1](https://tex.z-dn.net/?f=pH%20%3D%20-Log%20%28%5BH%5E%7B%2B%7D%5D%29%20%3D%201)
were [H^{+}] is the concentration of protons of the solution. Therefore it is necessary to know the concentration of the protons for every solution in order to solve the problem.
(a) and (c) are strong acids so they dissociate completely in aqueous solution. Thus, the concentration of the acid is the same as the protons.
(b) and (e) are strong bases so they dissociate completely in aqueous solution too. Thus, the concentration of the base is the same as the oxydriles. But in this case it is necessary to consider the water autoionization to calculate the protons concentration:
![K_{w} =[H^{+} ][OH^{-}]=10^{-14}](https://tex.z-dn.net/?f=K_%7Bw%7D%20%3D%5BH%5E%7B%2B%7D%20%5D%5BOH%5E%7B-%7D%5D%3D10%5E%7B-14%7D)
clearing the ![[H^{+} ]](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%20%5D)
![[H^{+} ]=\frac{10^{-14}}{[OH^{-}]}](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%20%5D%3D%5Cfrac%7B10%5E%7B-14%7D%7D%7B%5BOH%5E%7B-%7D%5D%7D)
(d) is a weak base so it is necessary to solve the equilibrium first, knowing 
The reaction is
→
so the equilibrium is

clearing the <em>x</em>

![x=[H^{+}]=4.93x10^{-10}](https://tex.z-dn.net/?f=x%3D%5BH%5E%7B%2B%7D%5D%3D4.93x10%5E%7B-10%7D)
Answer:
A
Explanation:
Coupled reactions are reactions in which endergonic reactions obtain the energy to go forward from exergonic reactions.
When benzene diazonium chloride interacts with phenol, the para position of the phenol molecules is associated with the diazonium salt, resulting in
p-hydroxyazobenzene. The coupling reaction is the name given to this process.