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Vera_Pavlovna [14]
3 years ago
9

Earth is currently 150 million km away from the Sun. If Earth was 200 million km away from the Sun, why would it no longer be ab

le to support life?
Chemistry
1 answer:
timurjin [86]3 years ago
4 0

Answer:

The temperature would be too cold

Explanation:

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How do you write 3.40 x 10 to the eighth power in standard form?
solong [7]

Answer:

272

Explanation:

hope it helps i double checked the math :D

7 0
3 years ago
Which one of the following descriptions relating to nuclear reactions is correct?
monitta

Answer: option D - The total number of nucleons changes.

Explanation:

Nuclear Reaction is best described as a process such as the fission of an atomic nucleus, or the fusion of one or more atomic nuclei and / or subatomic particles in which the NUMBER of PROTONS and / or NEUTRONS in a nucleus CHANGES; the reaction products may contain a different element or a different isotope of the same element.

Note that the NUCLEONS refers to ONE of the subatomic particles of the atomic nucleus, i.e. a PROTON or a NEUTRON.

So, in a Nuclear reaction, the total number of nucleons changes.

4 0
3 years ago
Lipid-soluble hormones usually bind to __________ receptors.
kumpel [21]

Answer:...intercellular receptors

Explanation:

Lipophilic hormone also known as lipid-soluble hormones can pass through the cell's plasma membrane, to bind to intracellular receptors, so as to effect change in gene expression.

3 0
3 years ago
Calculate the standard enthalpy change for the reaction at 25 ∘ C. Standard enthalpy of formation values can be found in this li
Anastasy [175]

Answer:

-179.06 kJ

Explanation:

Let's consider the following balanced reaction.

HCl(g) + NaOH(s) ⟶ NaCl(s) + H₂O(l)

We can calculate the standard enthalpy change for the reaction (ΔH°r) using the following expression.

ΔH°r = 1 mol × ΔH°f(NaCl(s)) + 1 mol × ΔH°f(H₂O(l)) - 1 mol × ΔH°f(HCl(g)) - 1 mol × ΔH°f(NaOH(s))

ΔH°r = 1 mol × (-411.15 kJ/mol) + 1 mol × (-285.83 kJ/mol) - 1 mol × (-92.31 kJ/mol) - 1 mol × (-425.61 kJ/mol)

ΔH°r = -179.06 kJ

7 0
3 years ago
What is the specific heat of a substance if 1450 calories are required to raise the temperature of a 240g sample by 20℃?
bazaltina [42]

Answer:

6960 J/kg°C

Explanation:

specific heat= mass×specific heat capacity×increase in temperature

specific heat= 0.240×1450×20= 6960 J/kg°C

hope it helps!

5 0
2 years ago
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