2000 km/sec. Convert that to m/sec.

Describe endothermic vs. exothermic reactions in terms of product formation. (hint: what happens when products are formed?)

shusha [124]

Answer:

Endothermic reaction chemical equation

Reactnt A + Reactant B + Heat (energy) ⇒ Products

Exothermic reaction chemical equation

Reactnt A + Reactant B ⇒ Products + Heat (energy)

Explanation:

Endothermic Reaction

An endothermic reaction is a reaction that reaction that requires heat before it would take place resulting in the absorption of heat from the surrounding that can be sensed by the coolness of the reacting system

An example of an endothermic reaction is a chemical cold pack that becomes cold when the chemical and water inside it reacts

Exothermic Reaction

An exothermic reaction is one that rekeases energy to the surroundings when it takes place. This is as a result of the fact that the combined heat energy of the reactants is more than the chemical heat energy of the products. An example of an exothermic reaction is a burning candle

5 0

3 years ago

Draw the structural formula for fatty acid C 18:2 9 a 12a

qwelly [4]

Answer:

............................................................................

Explanation:

7 0

3 years ago

What mass, in grams, of CO2 and H2O is formed from 2.55 mol of propane?

oksian1 [2.3K]

Answer:

336.6 grams of CO₂ and 183.6 grams of H₂O are formed from 2.55 moles of propane.

Explanation:

In this case, the balanced reaction is:

C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of reactant and product participate in the reaction:

C₃H₈: 1 mole
O₂: 5 moles
CO₂: 3 moles
H₂O: 4 moles

Being the molar mass of each compound:

C₃H₈: 44 g/mole
O₂: 16 g/mole
CO₂: 44 g/mole
H₂O: 18 g/mole

Then, by stoichiometry, the following quantities of mass participate in the reaction:

C₃H₈: 1 mole* 44 g/mole= 44 grams
O₂: 5 moles* 16 g/mole= 80 grams
CO₂: 3 moles* 44 g/mole= 132 grams
H₂O: 4 moles* 18 g/mole= 72 grams

So you can apply the following rules of three:

If by stoichiometry 1 mole of C₃H₈ forms 132 grams of CO₂, 2.55 moles of C₃H₈ how much mass of CO₂ will it form?

$mass of CO_{2} =\frac{2.55 moles of C_{3} H_{8}*132 gramsof CO_{2} }{ 1 mole of C_{3} H_{8}}$

mass of CO₂= 336.6 grams

If by stoichiometry 1 mole of C₃H₈ forms 72 grams of H₂O, 2.55 moles of C₃H₈ how much mass of H₂O will it form?

$mass of H_{2}O =\frac{2.55 moles of C_{3} H_{8}*72 gramsof H_{2}O }{ 1 mole of C_{3} H_{8}}$

mass of H₂O= 183.6 grams

336.6 grams of CO₂ and 183.6 grams of H₂O are formed from 2.55 moles of propane.

3 0

3 years ago

Need help ASAP please!

bearhunter [10]

Answer:

13 mol NO

Explanation:

Step 1: Write the balanced equation

4 NH₃(g) + 5 O₂(g) ⇒ 4 NO(g) + 6 H₂O(g)

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of O₂ to NO is 5:4.

Step 3: Calculate the number of moles of O₂ needed to produce 16 moles of NO

We will use the previously established molar ratio.

16 mol O₂ × 4 mol NO/5 mol O₂ = 13 mol NO

3 0

3 years ago

An aqueous solution of calcium hydroxide is standardized by titration with a 0.112 M solution of hydrobromic acid. If 15.2 mL of

TiliK225 [7]

Answer:

0.0457 M

Explanation:

The reaction that takes place is:

2HBr + Ca(OH)₂ → CaBr₂ + 2H₂O

First we calculate how many moles of acid reacted, using the HBr solution's concentration and volume:

Molarity = Moles / Volume

Molarity * Volume = Moles

0.112 M * 12.4 mL = 1.389 mmol HBr

Now we convert HBr moles to Ca(OH)₂ moles, using the stoichiometric ratio:

1.389 mmol HBr * $\frac{1mmolCa(OH)_{2}}{2mmolHBr}$ = 0.6944 mmol Ca(OH)₂

Finally we calculate the molarity of the Ca(OH)₂ solution, using the given volume and calculated moles:

0.6944 mmol Ca(OH)₂ / 15.2 mL = 0.0457 M

7 0

3 years ago