Answer:
please give a photo I can't now to help u
The first step is to balance the equation:
<span>C3H8 + 5O2 ---> 3CO2 + 4H2O
Check the balance
element left side right side
C 3 3
H 8 4*2 = 8
O 5*2=10 3*2 + 4 = 10
Then you have the molar ratios:
3 mol C3H8 : 5 mol O2 : 3 mol CO2 : 4 mol H2O
Now you have 40 moles of O2 so you make the proportion:
40.0 mol O2 * [3 mol CO2 / 5 mol O2] = 24.0 mol CO2.
Answer: option D. 24.0 mol CO2
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Answer:
2.76 × 10⁻¹¹
Explanation:
I don’t have access to the ALEKS Data resource, so I used a different source. The number may be different from yours.
1. Calculate the free energy of formation of CCl₄
C(s)+ 2Cl₂(g)→ CCl₄(g)
ΔG°/ mol·L⁻¹: 0 0 -65.3
ΔᵣG° = ΔG°f(products) - ΔG°f(reactants) = -65.3 kJ·mol⁻¹
2. Calculate K
T = (25.0 + 273.15) K = 298.15 K
Well, gold is way different form other say for instance what if you get a really good ring not to expensive or cheap, but its in between those characteristics what if u get a gold ring to compare now one might tarnish or fade, but if you really look at it that gold one will not it really all dependents on what metals your talking about cause all metals aren't the same some fade and some don't . Also the oxygen level is weak for other metals, but gold it different it can still keeps its shine .
- That's the best explanation i can give IF ITS NOT ENUH OR NOT RIGHT JUH COMMENT BELOWW↓↓ I WILL THINK OF SOMEThING ELSE THANKS! YOU HAVE A GREAT DAYY .
